What is the Value of d

Mathematics

1 answer:

Xelga [282]3 years ago

7 0

Step-by-step explanation:

$\sqrt{4 \times 9 \times 16} = \sqrt{4} \times \sqrt{9} \times \sqrt{16} = 2 \times 3 \times 4 = 24$

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The ratio of the number of Sam's CDs to the number of Alice's CD's is 7 to 8. Sam has 84 CDS.

Alex

Answer:

180 CDs

Step-by-step explanation:

So if Sam has 84 CDs, and the ratio from Sam to Alice is 7:8, we can do 84/7=12 so each number is equal to 12. Then we add up 7 and 8 and get 15, so we do 15*12 and we get 180.

7 0

2 years ago

PLEASE HELP!!! ASAP!!!!!!!!!!!!!!! 10 POINTS

I am Lyosha [343]

$1800|2\\.\ 900|2\\.\ 450|2\\.\ 225|5\\.\ \ 45|5\\.\ \ \ 9|3\\.\ \ \ 3|3\\.\ \ \ 1|\\\\1880=2\cdot2\cdot2\cdot5\cdot5\cdot3\cdot3=2^3\cdot5^2\cdot3^2\\\\Answer:\ \boxed{2^3\cdot3^2\cdot5^2}$

$\sqrt[3]{320}\\\\320|2\\160|2\\.\ 80|2\\.\ 40|2\\.\ 20|2\\.\ 10|2\\.\ \ 5|5\\.\ \ 1|\\\\320=2\cdot2\cdot2\cdot2\cdot2\cdo2\cdot5=2^3\cdot2^3\cdot5=2^3\cdot2^3\cdot\\\\\sqrt[3]{320}=\sqrt[3]{2^3\cdot2^3\cdot5}=\sqrt[3]{2^3}\cdot\sqrt[3]{2^3}\cdot\sqrt[3]{5}=2\cdot2\sqrt[3]{5}=4\sqrt[3]5\\\\Answer:\ \boxed{\sqrt[3]{320}=4\sqrt[3]{5}}$

4 0

3 years ago

Read 2 more answers

How do you find the derivative of 1/logx?

valentina_108 [34]

The derivative of 1/logx is With the chain rule.

1log(x)=log(x)−1 is ,= -1xlog(x)2 .

The by-product of logₐ x (log x with base a) is 1/(x ln a). Here, the thrilling issue is that we have "ln" withinside the by-product of "log x". Note that "ln" is referred to as the logarithm (or) it's miles a logarithm with base "e".

The by-product of 1/log x is -1/x(log x)^2. Note that 1/logx is the reciprocal of log.

$With the chain rule. \\ 1log(x)=log(x)−1 \\ So you follow the chain rule to the electricity after which to the log: \\ ddxlog(x)−1=−1⋅log(x) \\ \\−2⋅ddxlog(x) \\ =−1log(x)21x \\ =−1xlog(x)2 .$