Question

If m = (3x-1) and n = (3x+1),sjow that x² = mn+1 by 9​

Answer 1

Step-by-step explanation:

${x}^{2} = \frac{mn + 1}{9}$

$(3x - 1)(3x + 1)$

$9 {x}^{2} - 1$

${x}^{2} = \frac{9 {x}^{2 } - 1 + 1 } {9}$

${x}^{2} = \frac{9 {x}^{2} }{9}$

${x}^{2} = {x}^{2}$

So this identity is true.