3 years ago

For the curve y = ln(x 2 − 3), find the equation of the tangent line at (2, 0).

Mathematics

1 answer:

denis23 [38]3 years ago

3 0

Y' = 2x/(x^2 -3) y'(2) = 4
Using the point slope equation:
y-0 = 4(x-2)
y = 4x - 8

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In the diagram below segment DEF is shown(since all three letters are shown, they are collinear). If DE=3x+2, EF= x+5, and DF= 2

amm1812

The value of $x$ is 4.

By Geometry, we know that line segment $DF = DE + EF$ , which is equivalent to:

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We kindly invite to see this question on line segments: brainly.com/question/23297288

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