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mario62 [17]
3 years ago
10

Danny, Pedro, Derick, Jose, and Willy went to a soccer game. They each got a $3-off coupon to buy themselves a ticket to the gam

e. The tickets cost them $37. What is the price of one ticket?
Mathematics
1 answer:
kondor19780726 [428]3 years ago
3 0
I think it’s 22.4
the total is 37 then divided by 5 for each person. after you divide you add the $3 coupon so for each person would be 3 by 5 to equal 15. so 37 divided by 5 is 7.4 and then add 15 to get 22.4. If this is wrong please correct me :)
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In Navada, sales tax are 6.18%. what is the tax on items that total $111.39 before tax?
Harrizon [31]
The answer would be $104.5 
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3 years ago
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janie has 196 rock and country cd's that she listens to at home if there are 76 more rock cd's than country cds how many of each
marshall27 [118]
There are 60 Country CDs and 136 Rock CDs.

Rock and country CDs = 196

Country CD = x
Rock CD = x + 76

Country CD + Rock CD = 196
x + (x + 76) = 196
2x = 196 - 76
2x = 120
2x / 2 = 120 / 2
x = 60   * number of Country CD

Rock CD = x + 76 = 60 + 76 = 136 

To check:
Country + Rock = 196
60 + 136 = 196
196 = 196

4 0
3 years ago
A child grew 3 1/4 inches one year and 4 3/4 inches the next year. How many inches did the child grow over the two years?
Marianna [84]

let's firstly convert the mixed fractions to improper fractions, and then use the LCD, which in this case is 4, to sum them up.


\bf \stackrel{mixed}{3\frac{1}{4}}\implies \cfrac{3\cdot 4+1}{4}\implies \stackrel{improper}{\cfrac{13}{4}}~\hfill \stackrel{mixed}{4\frac{3}{4}}\implies \cfrac{4\cdot 4+3}{4}\implies \stackrel{improper}{\cfrac{19}{4}} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \cfrac{13}{4}+\cfrac{19}{4}\implies \stackrel{\textit{using the LCD of 4}}{\cfrac{13+19}{4}}\implies \cfrac{32}{4}\implies 8

5 0
3 years ago
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Solve the equation for all real values of x.<br> cosxtanx - 2 cos x=-1
IceJOKER [234]

Solution to equationcosxtanx - 2 cos^2 x=-1 for all real values of x is  x=2k\pi + \frac{\pi}{6}  , x=2k\pi + \frac{5\pi}{6} .

<u>Step-by-step explanation:</u>

Here we have , cosxtanx - 2 cos^2 x=-1. Let's solve :

⇒  cosxtanx - 2 cos^2 x=-1

⇒  cosx(\frac{sinx}{cosx}) - 2 cos^2 x=-1

⇒  sinx = 2 cos^2 x-1

⇒  sinx = 2 (1-sin^2x)-1

⇒  sinx = 1-2sin^2x

⇒  2sin^2x+sinx-1=0

By quadratic formula :

⇒ sinx = \frac{-b \pm \sqrt{b^2-4ac} }{2a}

⇒ sinx = \frac{-1 \pm \sqrt{1^2-4(2)(-1)} }{2(2)}

⇒ sinx = \frac{-1 \pm3}{4}

⇒ sinx = \frac{1}{2} , sinx =-1

⇒ sinx = sin\frac{\pi}{6} , sinx = sin\frac{3\pi}{2}

⇒ x=\frac{\pi}{6} , x=\frac{3\pi}{2}

But at x=\frac{3\pi}{2} we have equation undefined as cos\frac{3\pi}{2}=0 . Hence only solution is :

⇒ x=\frac{\pi}{6}

Since , sin(\pi -x)=sinx

⇒ x=\pi -\frac{\pi}{6} = \frac{5\pi}{6}

Now , General Solution is given by :

⇒ x=2k\pi + \frac{\pi}{6}  , x=2k\pi + \frac{5\pi}{6}

Therefore , Solution to equationcosxtanx - 2 cos^2 x=-1 for all real values of x is  x=2k\pi + \frac{\pi}{6}  , x=2k\pi + \frac{5\pi}{6} .

3 0
3 years ago
Find the vertex of the function. <br> y=x^2+6x+8
galben [10]

Answer:

(-3,-1)

Step-by-step explanatio

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