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sasho [114]
3 years ago
10

I had a summer job cooking two items at a bbq place. I sell burgers for $9.00 and sell chicken sandwiches for $11.25. Because I

am a splendid cook, i sell a total of 330 items and make a total of $3,375. How many of each did I sell?
Mathematics
1 answer:
pishuonlain [190]3 years ago
8 0

Answer:

He sold 180 chicken sandwiches and 150 burguers.

Step-by-step explanation:

Since 330 items were sold, then the amount of burguers and chicken sandwiches sold must be equal to this value. From this information we have:

burguers + sandwiches = 330

We know that each burguer cost $9 and each chicken sandwich cost $11.25 and that we made a total of $3,375. So we have:

9*burguers + 11.25*sandwiches = 3,375

From the first equation we have:

burguers = 330 - sandwiches

Applying it on the second equation:

9*(330 - sandwiches) + 11.25*sandwiches = 3,375

2,970 - 9*sandwiches + 11.25*sandwiches = 3,375

2.25*sandwiches = 3,375 - 2,970

2.25*sandwiches = 405

sandwiches = 405/2.25 = 180

So,

burguers = 330 - 180  = 150

He sold 180 chicken sandwiches and 150 burguers.

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<u>Answer:</u>

The equation to describe the relationship between Elena distance:

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<u>Solution:</u>

Given, Elena bikes 20 minutes each day for exercise.  

We have to write an equation to describe the relationship between her distance in miles, D, and her biking speed, in miles per hour,  

We know that, distance travelled = speed \times time

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\mathrm{D}=13 \text { miles per hour } \times \frac{20}{60} \text { hours } \rightarrow \mathrm{d}=13 \times \frac{1}{3} \rightarrow \mathrm{d}=4.34 \text { miles approximately. }

b. At a constant speed of 15 minutes per hour for the first 5 minutes, then at 12 miles per hour for the last 15 minutes  

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\begin{array}{l}{\mathrm{D}=15 \mathrm{mph} \times 5 \text { minutes }+12 \mathrm{mph} \times 15 \text { minutes }} \\\\ {\mathrm{D}=15 \mathrm{mph} \times \frac{5}{60} \text { hours }+12 \mathrm{mph} \times \frac{15}{60} \text { minutes }} \\\\ {\mathrm{D}=15 \times \frac{1}{12}+12 \times \frac{1}{4} \rightarrow \mathrm{D}=\frac{5}{4}+3 \rightarrow \mathrm{D}=3+1.25 \rightarrow \mathrm{D}=4.25 \mathrm{miles}}\end{array}

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Now, total distance travelled = distance travelled with M mph + distance travelled with N mph

D = M mph \times 5 minutes + N mph \times 15 minutes

\mathrm{D}=\mathrm{M} \mathrm{mph} \times \frac{5}{60} \text { hours }+\mathrm{N} \mathrm{mph} \times \frac{15}{60} \text { minutes }

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Answer:

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Step-by-step explanation:

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See below for answers and explanations

Step-by-step explanation:

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The slope, b=0.16, means that for every 1 point earned for a student's pre-exam total, their final exam score will increase by 0.16 points for each point they earned on the pre-exam.

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Hope you understand, and never stop striving to learn!

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