Answer:
The median is usually preferred in these situations because the value of the mean can be distorted by the outliers. However, it will depend on how influential the outliers are. If they do not significantly distort the mean, using the mean as the measure of central tendency will usually be preferred.
Answer:
answer below
Step-by-step explanation:
in this case the decimal will be recurring so 1 and 2 thirds is 1.6 recurring and 2 and 7 nigths is 2.7 recurring so just plot in between the intervals so the first one could be between 1.6 and 1.7 and the sexond between 2.7 and 2.8
Answer:
0.5
Step-by-step explanation:
2/2^2
= 2/4
= 1/2
= 0.5
Answer:

Step-by-step explanation:
sorry I didn't write it out...