Answer:
jkjjjjjjujhhhgvvvvvgvhjjhhhgvvg
The probability of occurrence for the events A, B and C is; 1/4.
<h3>What is the probability of occurrence of.the described events?</h3>
For the first event A in which case, there's no odd number on the first two rolls, the possible events are; EEE and EEO. Consequently, the required probability is;
Event A = 2/8 = 1/4.
For the event B in which case, there's an even number on both the first and last rolls; the possible events are; EEE and EOE. Consequently, the required probability is;
Event B = 2/8 = 1/4.
For the event C in which case, there's an odd number on each of the first two rolls; the possible events are; OOO and OOE. Consequently, the required probability is;
Event C = 2/8 = 1/4.
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Answer: 3 for the first one. and 2 for the second
So I would first find out when they are equal then do one more than that. 21x=18x+45, 3x=45, x=15 so the answer would be 16 jerseys