Question

9. Consider the line y = 4x+9. If a second line is perpendicular to this one, what is its slope? please show your work, i will mark brainliest!

Answer 1

Answer:

The slope-intercept form is  y=mx+b, where  m  is the slope and  b  is the y-intercept.

y=mx+b

Using the slope-intercept form, the slope is  4

.

m=4

The equation of a perpendicular line to  

y=4x−9

must have a slope that is the negative reciprocal of the original slope.

m perpendicular

=$\frac{1}{4}$   sorry this is wrong it should be =-$\frac{1}{4}$

Hope this helps have a good day

Answer 2

Answer:

Slope of the line perpendicular to the given line = $- \frac{1}{4}$

Step-by-step explanation:

If two are lines are perpendicular to each other,

the product of their slopes = - 1 .

That is ,

      $m_ 1 \times m_2 = -1$

Slope of the given line :

$m_ 1 = 4$

Hence slope of the line perpendicular to it :

                                                                $4 \times m_ 2 = - 1 \\\\\frac{4}{4} \times m_2 = - \frac{1}{4} \\\\1 \times m_2 = - \frac{1}{4}\\\\m_ 2 = \frac{-1}{4}$