All categories

3 years ago

Write the equation of a line, in slope-intercept form (1,1);(-2,-11) Y =

Mathematics

2 answers:

bonufazy [111]3 years ago

6 0

Answer:

Y =4X -3

Step-by-step explanation:

x1 y1 x2 y2

1 1 -2 -11

(Y2-Y1) (-11)-(1)= -12 ΔY -12

(X2-X1) (-2)-(1)= -3 ΔX -3

slope= 4

B= -3

Y =4X -3

PSYCHO15rus [73]3 years ago

4 0

Answer:

y=4x-3

Step-by-step explanation:

Hi there!

We are given the points (1,1) and (-2, -11) and we want to write the equation of the line in slop-intercept form

Slope-intercept form is given as y=mx+b, where m is the slope and b is the y intercept

So let's find the slope of the line

The formula for the slope calculated from two points is $\frac{y_2-y_1}{x_2-x_1}$ , where $(x_1, y_1)$ and $(x_2, y_2)$ are points

We have everything we need to calculate the slope, let's just label the points to avoid confusion

$x_1=1\\y_1=1\\x_2=-2\\y_2=-11$

Now substitute those values into the formula

m= $\frac{y_2-y_1}{x_2-x_1}$

m= $\frac{-11-1}{-2-1}$

Subtract

m= $\frac{-12}{-3}$

Divide

m=4

So the slope of the line is 4

Here is the equation of the line so far:

y=4x+b

We need to find b

As the equation passes through both (1,1) and (-2, -11), we can plug either one of them into the equation to solve for b

Taking (1,1) will give us this:

1=4(1)+b

Multiply

1=4+b

Subtract 4 from both sides

-3=b

Substitute -3 as b into the equation

y=4x-3

Hope this helps!

You might be interested in

Barbara plotted an elevation below sea level on a number line and labeled it A. She plotted point B above o, a distance that is

stellarik [79]

Answer: Because Point A is negative and the same distance below 0 on the number line as Point B is above it, Point B is both positive and the opposite of Point A.

7 0

3 years ago

Read 2 more answers

Maria practice the piano 5/6 of an hour everyday. How many hours does she practice in 4 days

S_A_V [24]

Answer:
10/3 hours

Explanation:
If Maria practices 5/6 hours a day, then she practices (5/6)(4) hours in 4 days.

(5/6)(4)=20/6

20/6 can be simplified to 10/3 hours.

I hope this helps!

3 0

2 years ago

(04.01) Which point could be removed in order to make the relation a function? (4 points) {(0, 2), (3, 8), (−4, −2), (3, −6), (−

umka21 [38]

A function will not have any repeating x values...it can have repeating y values, just not the x ones

{(0,2),(3,8),(-4,-2),(3,-6),(-1,8),(8,3)}
u would have to remove one of the sets of points that has 3 as its x value....so either remove (3,8) or (3,-6)....because with both of them in there, u have repeating x values

7 0

3 years ago

Read 2 more answers

Somebody please help so I can pass, please

ASHA 777 [7]

First, we are going to find the vertex of our quadratic. Remember that to find the vertex $(h,k)$ of a quadratic equation of the form $y=a x^{2} +bx+c$ , we use the vertex formula $h= \frac{-b}{2a}$ , and then, we evaluate our equation at $h$ to find $k$ .

We now from our quadratic that $a=2$ and $b=-32$ , so lets use our formula:
$h= \frac{-b}{2a}$
$h= \frac{-(-32)}{2(2)}$
$h= \frac{32}{4}$
$h=8$
Now we can evaluate our quadratic at 8 to find $k$ :
$k=2(8)^2-32(8)+56$
$k=2(64)-256+56$
$k=128-200$
$k=-72$
So the vertex of our function is (8,-72)

Next, we are going to use the vertex to rewrite our quadratic equation:
$y=a(x-h)^2+k$
$y=2(x-8)^2+(-72)$
$y=2(x-8)^2-72$
The x-coordinate of the minimum will be the x-coordinate of the vertex; in other words: 8.

We can conclude that:
The rewritten equation is $y=2(x-8)^2-72$
The x-coordinate of the minimum is 8