Question

Write the equation of a line, in slope-intercept form (1,1);(-2,-11) Y =

Answer 1

Answer:

Y =4X  -3

Step-by-step explanation:

x1 y1  x2 y2

1 1  -2 -11

   

(Y2-Y1) (-11)-(1)=   -12  ΔY -12

(X2-X1) (-2)-(1)=    -3  ΔX -3

   

slope= 4          

B= -3          

   

Y =4X  -3    

Answer 2

Answer:

y=4x-3

Step-by-step explanation:

Hi there!

We are given the points (1,1) and (-2, -11) and we want to write the equation of the line in slop-intercept form

Slope-intercept form is given as y=mx+b, where m is the slope and b is the y intercept

So let's find the slope of the line

The formula for the slope calculated from two points is $\frac{y_2-y_1}{x_2-x_1}$, where $(x_1, y_1)$ and $(x_2, y_2)$ are points

We have everything we need to calculate the slope, let's just label the points to avoid confusion

$x_1=1\\y_1=1\\x_2=-2\\y_2=-11$

Now substitute those values into the formula

m=$\frac{y_2-y_1}{x_2-x_1}$

m=$\frac{-11-1}{-2-1}$

Subtract

m=$\frac{-12}{-3}$

Divide

m=4

So the slope of the line is 4

Here is the equation of the line so far:

y=4x+b

We need to find b

As the equation passes through both (1,1) and (-2, -11), we can plug either one of them into the equation to solve for b

Taking (1,1) will give us this:

1=4(1)+b

Multiply

1=4+b

Subtract 4 from both sides

-3=b

Substitute -3 as b into the equation

y=4x-3

Hope this helps!