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slava [35]
3 years ago
6

A glass company is repairing a window in the shape of an equilateral triangle. If the length of one side of the triangle is 17 i

nches and the company charges $12 per square inch, the cost of the replacement window will be $___.
Mathematics
1 answer:
nalin [4]3 years ago
4 0

Answer:

the cost of the replacement window will be $<u>1501.44</u>.

Step-by-step explanation:

area of an equilateral triangle:

A = \frac{\sqrt{3}}{4} a^{2}

A = (√3)/4 * (17)^2

A = 125.12 in^2

125.12 * 12 = <u>$1501.44</u>

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Match the following items.
Misha Larkins [42]

Based on the points on the graph, the correct matches are:

  • A - (-4, -2).
  • B - .(2, -4)
  • C - (4, -2).
  • D - (2, 5)
  • E - (-1, 1)
  • F - (-5, 0)
  • G - (4, 2)
  • H - (0, -5)

<h3>How are points located on a graph?</h3>

To find a point, you need to look at the x-axis first and then the y-axis.

Find where the point is located on the x-axis, and then look for where the point intersects with the y-axis point.

For instance, the point A is located at (-4, -2) so look at the -4 point on the x axis, then go down to the -2 point on the y-axis. You'll find point A.

Find out more on the coordinates of points on graphs at brainly.com/question/11337174.

#SPJ1

5 0
2 years ago
20 POINTS!!!
Sever21 [200]

Answer:

a) 54 m is your answer

Step-by-step explanation:

Given: s = 9

The formula given is:

P (Perimeter) = 6s

Plug in 9 for s

P = 6(9)

Multiply.

P = 6(9)

P = 54

a) 54 m is your answer

~

3 0
3 years ago
Read 2 more answers
If angle I is congruent to angle K, find JK.
Rudiy27
Using Isosceles triangle theorem we can determine that JI = JK
Thus
5x + 4 = 2x+7
3x = 3
x=1
Plug it back into the eqution for JK
2(1) + 7 = JK
9 = JK

5 0
3 years ago
Read 2 more answers
A tuna can weighs eighty-five grams. What is the weight of eleven tuna cans?
Anika [276]

Answer:

85g*11=935g

Step-by-step explanation:

1 tuna can = 85g

11 tuna cans is= 1*11

so 85g*11

3 0
2 years ago
Read 2 more answers
Given a circle with centre O and radius 2.4cm. P is a point such that the lenght of the tengent from Q to the circle is 4.5cm. F
skelet666 [1.2K]

Answer:

5.1 cm

Step-by-step explanation:

(Probable) Question;

Given a circle with center <em>O</em> and radius 2.4 cm.<em> P</em> is a point on the tangent that touches the circle at point <em>Q</em>, such that the length of the tangent from <em>P </em>to <em>Q</em> is 4.5 cm. Find the length of OP

The given parameters are;

The radius of the circle with enter at <em>O</em>, \overline{OQ} = 2.4 cm

The length of the tangent from<em> P</em> to the circle at point <em>Q, </em>\overline{PQ} = 4.5 cm

The length of OP = Required

By Pythagoras's theorem, we have;

\overline{OP}² = \overline{OQ}² + \overline{PQ}²

∴ \overline{OP}² = 2.4² + 4.5² = 26.01

\overline{OP} = √26.01 = 5.1

The length of OP = 5.1 cm

8 0
3 years ago
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