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3 years ago

Out of a.) Framers b.) Federalists c.) Anti-Federalists d.) Boycott which one does not belong and explain why.

Advanced Placement (AP)

2 answers:

Travka [436]3 years ago

6 0

D. Boycott is your answer

The other 3 are all types of people, a group of people, while boycott is an action that is used by people

hope this helps

olga_2 [115]3 years ago

4 0

Answer: Option D- Boycott

<u>Explanation:</u>

Framers usually refer to any person who involves in shaping or creating any plan, concept, or system.

The term Federalists refers to any person who involves in advocating or supporting any system of government where there are several states that are united under a central authority.

Anti-federalists refer to any person who involves in opposing the Constitution of U.S adoption.

Boycott is the term referring to the withdrawal from any commercial or social relations with any organization, country, or person as a protest or punishment.

Since, Boycott refers to group of people and not a single person it is the answer.

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3 years ago

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3 years ago

If the wait time is less than 30 minutes for 75% of all patients in the emergency room, what is the probability that the

Greeley [361]

The probability that the proportion of patients who wait less than 30 minutes is 0.582 or less is 0.0020

<h3>What is probability? </h3>

Probability can be defined as the likelihood of an event to occur. In statistics, the mean of the sample distribution typically shows the probability of the population.

From the parameters given:

The sample size (n) = 55 patients
Let's assume that the mean (x) = 32 (i.e. 58.2%) of the patients

The sample proportion $\mathbf{\hat p}$ can be computed by using the expression:

$\mathbf{\hat p = \dfrac{x}{n}}$

$\mathbf{\hat p = \dfrac{32}{55}}$

$\mathbf{\hat p =0.582}$

If the percentage of the probability of all patients in the emergency room = 0.75

The probability that the proportion of patients who wait less than 30 minutes is 0.582 or less can be computed as:

$\mathbf{( \hat P \leq 0.582) = P \Big( \dfrac{\hat p - p}{\sqrt{\dfrac{p(1-p)}{n}}} \leq \dfrac{0.582 - 0.75}{\sqrt{\dfrac{0.75(1-0.75)}{55}}} \Big )}$