Which algebraic expression has a term with a coefficient of 9? O A. 6(x + 5) O B. 6x - 9 O C. 6+ x

Find the area of the other polygon area=__ft

Colt1911 [192]

Answer:

108ft^2

Step-by-step explanation:

since you going up in value, you mulitple 3*9 to get 27. that means you have to multiple the other value of the bigger rectangle by 2. therefore 6*18=108

3 0

3 years ago

MN0 with vertices M(4,-5), N(5,-8), O(8, -6) ; translate the new figure M'N'O' (-2,5)

Aleks04 [339]

If you are translating a graph (-2,5), the easiest way to find the new points is to subtract the x value of each coordinate (M, N, and O) by 2. This will give you the new x values for the translated coordinates. Then, to find the new y values, add 5 to the y values of each coordinate. Then put the new x value and new y value in the form of a coordinate, and that will be your answer.

5 0

3 years ago

A table decreased in price by 3/5.After the reduction it was priced at £32. What was the original

Stels [109]

Answer:

96 not too sure but i hope it is right sry.

Step-by-step explanation:

32x3=96

3 0

2 years ago

3) m_2 = x + 70 60° A) -10 C) 11 B)-6 D) 9

kogti [31]

Answer:

C

Step-by-step explanation:

7 0

3 years ago

Which of the following sets are subspaces of R3 ?

Ratling [72]

Answer:

The following are the solution to the given points:

Step-by-step explanation:

for point A:

$\to A={(x,y,z)|3x+8y-5z=2} \\\\\to for(x_1, y_1, z_1),(x_2, y_2, z_2) \varepsilon A\\\\ a(x_1, y_1, z_1)+b(x_2, y_2, z_2) = (ax_1+bx_2,ay_1+by_2,az_1+bz_2)$

$=3(aX_l +bX_2) + 8(ay_1 + by_2) — 5(az_1+bz_2)\\\\=a(3X_l+8y_1- 5z_1)+b (3X_2+8y_2—5z_2)\\\\=2(a+b)$

The set A is not part of the subspace $R^3$

for point B:

$\to B={(x,y,z)|-4x-9y+7z=0}\\\\\to for(x_1,y_1,z_1),(x_2, y_2, z_2) \varepsilon B \\\\\to a(x_1, y_1, z_1)+b(x_2, y_2, z_2) = (ax_1+bx_2,ay_1+by_2,az_1+bz_2)$

$=-4(aX_l +bX_2) -9(ay_1 + by_2) +7(az_1+bz_2)\\\\=a(-4X_l-9y_1+7z_1)+b (-4X_2-9y_2+7z_2)\\\\=0$

$\to a(x_1,y_1,z_1)+b(x_2, y_2, z_2) \varepsilon B$

The set B is part of the subspace $R^3$

for point C: $\to C={(x,y,z)|x$

In this, the scalar multiplication can't behold

$\to for (-2,-1,2) \varepsilon C$

$\to -1(-2,-1,2)= (2,1,-1)$ ∉ C

this inequality is not hold

The set C is not a part of the subspace $R^3$

for point D:

$\to D={(-4,y,z)|\ y,\ z \ arbitrary \ numbers)$

The scalar multiplication s is not to hold

$\to for (-4, 1,2)\varepsilon D\\\\\to -1(-4,1,2) = (4,-1,-2)$ ∉ D

this is an inequality, which is not hold

The set D is not part of the subspace $R^3$

For point E:

$\to E= {(x,0,0)}|x \ is \ arbitrary) \\\\\to for (x_1,0 ,0) ,(x_{2},0 ,0) \varepsilon E \\\\\to a(x_1,0,0) +b(x_{2},0,0)= (ax_1+bx_2,0,0)\\$

The $x_1, x_2$ is the arbitrary, in which $ax_1+bx_2$ is arbitrary

$\to a(x_1,0,0)+b(x_2,0,0) \varepsilon E$

The set E is the part of the subspace $R^3$

For point F:

$\to F= {(-2x,-3x,-8x)}|x \ is \ arbitrary) \\\\\to for (-2x_1,-3x_1,-8x_1),(-2x_2,-3x_2,-8x_2)\varepsilon F \\\\\to a(-2x_1,-3x_1,-8x_1) +b(-2x_1,-3x_1,-8x_1)= (-2(ax_1+bx_2),-3(ax_1+bx_2),-8(ax_1+bx_2))$

The $x_1, x_2$ arbitrary so, they have $ax_1+bx_2$ as the arbitrary $\to a(-2x_1,-3x_1,-8x_1)+b(-2x_2,-3x_2,-8x_2) \varepsilon F$

The set F is the subspace of $R^3$

5 0

3 years ago

Which algebraic expression has a term with a coefficient of 9? O A. 6(x + 5) O B. 6x - 9 O C. 6+ x - 9 O D. 9x=6​

Which algebraic expression has a term with a coefficient of 9? O A. 6(x + 5) O B. 6x - 9 O C. 6+ x - 9 O D. 9x=6