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Allisa [31]
3 years ago
14

Two people are pulling on a rope in order to get a 2250-kg car out of a mud puddle. One person pulls with a force of 600 N and t

he other pulls with a force of 800 N. There is a resistive frictional force of 1200 N. Use the acceleration found in the previous question to determine the distance they would pull the vehicle in 25s (answer with 2 digits, include properly abbreviated units) *
Mathematics
1 answer:
Sonbull [250]3 years ago
4 0

Answer:

Assuming both people are pulling in the same direction, the net force on the car is, according to Newton's second law,

600 N + 800 N - 1200 N = (2250 kg) a

Solve for the acceleration a :

200 N = (2250 kg) a

a = (200 N) / (2250 kg)

a ≈ 0.0889 m/s/s

Step-by-step explanation: I hope this helps!

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If VW≅VY, WX = s + 69, and XY = 4s, what is the value of s?
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<h2>Answer:</h2>

The value of s is 23°

<h2>Step-by-step explanation:</h2><h3>Known :</h3>
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