Answer:
95% confidence interval for the proportion of students supporting the fee increase is [0.767, 0.815]. Option C
Step-by-step explanation:
The confidence interval for a proportion is given as [p +/- margin of error (E)]
p is sample proportion = 870/1,100 = 0.791
n is sample size = 1,100
confidence level (C) = 95% = 0.95
significance level = 1 - C = 1 - 0.95 = 0.05 = 5%
critical value (z) at 5% significance level is 1.96.
E = z × sqrt[p(1-p) ÷ n] = 1.96 × sqrt[0.791(1-0.791) ÷ 1,100] = 1.96 × 0.0123 = 0.024
Lower limit of proportion = p - E = 0.791 - 0.024 = 0.767
Upper limit of proportion = p + E = 0.791 + 0.024 = 0.815
95% confidence interval for the proportion of students supporting the fee increase is between a lower limit of 0.767 and an upper limit of 0.815.
If by factoring (n + 7) (n + 4)
Answer:
Circumference = 39.6 cm
We know:
Circumference of a circle = 2πr
⇒39.6 =2×
22
7
×r⇒
39.6×7
2×22
=r⇒r=6.3 cm
Also,
Area of the circle = πr2
=
22
7
×6.3×6.3=124.74 cm2
Step-by-step explanation:
<em>#</em><em>C</em><em>arryOnLearning</em>
You would do ten columns of ten and then you would just do the remaining.
Answer:
main number
Step-by-step explanation:
