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lesantik [10]
2 years ago
5

Can anyone pls help me with this algebra question click to see a picture of the problem

Mathematics
2 answers:
zheka24 [161]2 years ago
7 0
The value of k is 6.

The vertex of f(x) is at (4, 1).  The vertex of g(x) is at (-2, 1).  It has been shifted left 6 units.  This means that the value of k must be -6 (when translating a function horizontally, the number we add/subtract is the opposite of what we would normally think; we think of left as negative, but to shift it left, we actually add).
irinina [24]2 years ago
6 0
From the given functions, it can be seen that the graph of g(x) represents a shift of 6 units to the left of the graph of f(x).

Given a function, f(x), a shift of k units to the left of f(x) is given by g(x + k).

Therefore, if g(x) = f(x + k), then k = 6.
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A winery has a vat with two pipes leading to it. The inlet pipe can fill the vat in 5 ​hours, while the outlet pipe can empty it
Rashid [163]

Answer:

                 time=40/3hours\approx 13.3hours

Step-by-step explanation:

The rates are additive: you can calculate the<em> inlet </em>rate and the <em>outlet</em> rate and add them algebraically, i.e. the inlet rate will be positive and the outlet rate will be negative.

<u>1. Inlet rate:</u>

1vat/5hours

<u />

<u>2. Outlet rate:</u>

1vat/8hours

<u>3. Net rate:</u>

            \text{Inlet rate - outlet rate}=1vat/5hours-1vat/8hours\\\\ \text{Net rate}=(8-5)vat/40hour=3vat/40hour=(3/40)vat/hour

<u>4. Time to fill the vat</u>

           rate=amount/time\implies time=amount/rate\\ \\ time=1vat/(3vat/40hour)

          time=40/3hours\approx 13.3hours

7 0
2 years ago
Solve the equation to find where the treste ground levelEnter your answers from least to greatest and round to the nearest The m
DaniilM [7]

Answer:

The trestle meets ground level at 0.875 units and 9.125 units

Step-by-step explanation:

Poorly formatted question.

The given equation is:

y = -x^2 + 10x - 8

Required

The point where the trestle gets to the ground level

To do this, we set y = 0

So, we have:

-x^2 + 10x - 8 = 0

Multiply through by -1

x^2 -10x + 8 = 0

Solve using quadratic formula:

x= \frac{-b \± \sqrt{b^2 - 4ac}}{2a}

Where:

a = 1; b =-10; c = 8

So, we have:

x= \frac{-(-10) \± \sqrt{(-10)^2 - 4*1*8}}{2*1}

x= \frac{-(-10) \± \sqrt{68}}{2*1}

x= \frac{-(-10) \± 8.25}{2}

x= \frac{10 \± 8.25}{2}

Solve the fraction

x= 5 \± 4.125

Split

x= 5 + 4.125\ or\ x= 5 - 4.125

x= 9.125\ or\ x= 0.875

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