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Nimfa-mama [501]
3 years ago
7

Solve the system by substitution. — бу = x x + y = -30

Mathematics
1 answer:
yawa3891 [41]3 years ago
6 0

Step-by-step explanation:

-6y + y=-30

-5y = -30

y=6

x=-6 ×6= -36

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3) Find the value of FD. bited F 12 12 13x - 16 E 4x+11 D​
vlada-n [284]

The Length of FD = 26 cm

According to the given information

FE = FC = 12cm

As FE, FC both are radius of circle

The tangent segments to a circle from a external point are equal

Hence

CD = ED

13x - 16 = 4x + 11

13x - 4x = 11 + 16

9x = 27

x = 27/9

x = 3

CD = 13x - 16

     = 13 × 3 - 16

     = 23 cm

ED = 4x + 11

     = 4 × 3 + 11

     = 23 cm

In Triangle FED

FE is perpendicular to ED

According to Pythagoras Theorem

FD^{2}= FE^{2}+ED^{2}

       = 12^{2}+ 23^{2}

       = 673

FD = 26 cm approx.

The Length of FD = 26 cm

To know more about Pythagoras Theorem

brainly.com/question/343682

#SPJ1

8 0
1 year ago
Im deleting brainly so heres my points!​
nadezda [96]

Answer:

thx you so much and why are you deleting it

3 0
3 years ago
Read 2 more answers
Please help meee I’m dont understand geometry please help me thank you
Dvinal [7]

Answer:

1) A,B,F,D

2)A,E,B,C

3)B,F,C,D

4)A,B,D,F

7 0
3 years ago
a pyramid whose altitude is 5ft weighs 800lbs. at what distance from its vertex must it be cut by a plane parallel to its base s
slavikrds [6]

A structure which has a square base and four triangular sides meeting at a point is called pyramid.

At distance of 3.97 feet from its vertex , pyramid is cut by plane  so that the two solids of equal weight will be formed.

<u>It is assumed that weight of pyramid is proportional to its volume.</u>

So,   w  = k V , where V is volume of original pyramid and v is volume of small pyramid and k is constant.

Let us consider that at h  distance,  pyramid is cut from its vertex. So a small pyramid is also formed.

Assume that base area of original pyramid is A and base of small pyramid is a.

Volume of original pyramid is,   V= \frac{1}{3}  *A* 5

So, weight of original pyramid,  W = k *(\frac{1}{3}  *A* 5) = 800

Volume of small pyramid is,  v = \frac{1}{3}* a* h

So, weight of small pyramid, w = k*(\frac{1}{3}* a* h)=400

<u>Since, base and height of small pyramid and original pyramid are in proportion.</u>

So,  \frac{a}{A}  = (\frac{h}{5}) ^{2}

       a = (\frac{h}{5} )^{2}A

Substituting value of a in  equation k*(\frac{1}{3}* a* h)=400

So, k*(\frac{1}{3}* \frac{h^{2} }{25}A * h)=400

       (k*\frac{1}{3}* A*5)*\frac{1}{5} *\frac{h^{2} }{25} * h)=400

Since, (k *\frac{1}{3}  *A* 5) = 800, substitute in above equation.

    So, 800*\frac{h^{3} }{125}=400\\\\h^{3}=\frac{125}{2}\\\\h=\sqrt[\frac{1}{3} ]{62.5}\\\\h=3.97 feet

Learn more:

brainly.com/question/17950304

6 0
2 years ago
Read 2 more answers
Samantha has 1/3 gallon of milk left and wants to make 55 smoothies. If she wants to use the same amount of milk in each smoothi
Bingel [31]

Answer:

She can put 1/165 in one smoothie.

Step-by-step explanation:

1/3 divided by 55/1

1/3 x 1/55 = 1/165

Hope this helps! :)

plz make me the Brainiest

6 0
3 years ago
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