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yaroslaw [1]
2 years ago
10

A hydro company is laying down power lines in the ground. They have two sections of cable so far that are 325.0 m and 430.0 m lo

ng. These two sections of power lines meet at an angle of 23°. How much extra cable is necessary to connect the two pieces of existing cable? Round to the nearest metre.
Mathematics
1 answer:
Hoochie [10]2 years ago
3 0

The length of extra cable that is required to connect the two pieces of existing cable is equal to 182 meters.

<h3>How to determine the length of extra cable?</h3>

In order to determine the length of extra cable that is required to connect the two pieces of existing cable, we would apply the law of cosine as follows:

B² = A² + C² - 2(A)(C)cosB

Substituting the given parameters into the formula, we have;

B² = 325.0² + 430.0² - 2(325.0)(430.0)cos23

B² = 105,625 + 184,900 - 279,500(0.9205)

B² = 290,525 - 257,279.75

B² = 33,245.25

B = √33,245.25

B = 182.33 ≈ 182 meters.

Read more on cosine law here: brainly.com/question/11000638

#SPJ1

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shutvik [7]

Answer:

1712

Step-by-step explanation:

100%-48%=52%

52-48=4

4% more.

42,800*0.04

1712

3 0
2 years ago
Read 2 more answers
The state education commission wants to estimate the fraction of tenth grade students that have reading skills at or below the e
Korolek [52]

Answer:

A sample of 499 is needed.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

The margin of error is given by:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

In this question, we have that:

\pi = 0.21

90% confidence level

So \alpha = 0.1, z is the value of Z that has a pvalue of 1 - \frac{0.1}{2} = 0.95, so Z = 1.645.

How large a sample would be required in order to estimate the fraction of tenth graders reading at or below the eighth grade level at the 90% confidence level with an error of at most 0.03

We need a sample of n, which is found when M = 0.03. So

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.03 = 1.645\sqrt{\frac{0.21*0.79}{n}}

0.03\sqrt{n} = 1.645\sqrt{0.21*0.79}

\sqrt{n} = \frac{1.645\sqrt{0.21*0.79}}{0.03}

(\sqrt{n})^2 = (\frac{1.645\sqrt{0.21*0.79}}{0.03})^2

n = 498.81

Rounding up

A sample of 499 is needed.

8 0
2 years ago
If 3220 = 80+7, what is the value of c?
Setler79 [48]

Answer:

Correct option is

C

36.25

Modal class =30−40

So we have, l=30,f0=12,f1=32,f2=20 and h=10

⇒  Mode=l+2f1−f0f2f1−f0×h

                  =30+2×32−12−2032−12×10

                  =30+6.25

                  =36.25

∴  Mode =36.25

8 0
3 years ago
Sekhar gives a quarter of his sweets to Renu and then gives 5 sweets to Raji. He has
Feliz [49]

Answer:

16 sweets

Step-by-step explanation:

Number of sweet that Sekhar had = x

Sweets given to Renu = (1/4) of x = \frac{1}{4}x

Sweets given to Raji = 5

Remaining sweets = 7

x = \frac{1}{4}x +5 + 7\\\\x -\frac{1}{4}x = 12\\\\\frac{4*x}{1*4}x-\frac{1}{4}x = 12\\\\\frac{4x}{4}-\frac{1}{4}x= 12\\\\\frac{3x}{4}=12\\\\x = 12*\frac{4}{3}\\\\x=4*4\\\\x=16

6 0
2 years ago
Are these ratios equivalent?
Mekhanik [1.2K]
The first one YES and the last one NO!
7 0
3 years ago
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