Write these following fractions in order from greatest to least 1/9 1/2 1/8

Mathematics

1 answer:

irinina [24]3 years ago

8 0

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$\frac{1}{9} = \frac{1 \times 8}{9 \times 8} = \frac{8}{72} \\$

$\frac{1}{2} = \frac{1 \times 36}{2 \times 36} = \frac{36}{72} \\$

$\frac{1}{8} = \frac{1 \times 9}{8 \times 9} = \frac{9}{72} \\$

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$\frac{8}{72} < \frac{9}{72} < \frac{36}{72} \\$

$\frac{1}{9} < \frac{1}{8} < \frac{1}{2} \\$

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Thus the order from greatest to least is :

$\frac{1}{2} \: , \: \frac{1}{8} \: , \: \frac{1}{9} \\$

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Step-by-step explanation:

Problem 1

For the first problem, we first want to find y so that we can plug it into the expression.

We can use elimination method for the system of equations to solve.

3x+3y=21

3x-y=5

We subtract both equations to eliminate x.

4y=16 [divide both sides by 4]

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Now that we know y, we can plug it into the expression.

$\frac{4}{2} -3$ [divide]

$2-3$ [subtract]

$-1$

We know that the answer is A.

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Problem 2

For the second problem, we need to know how to calculate percent error. The formula for precent error is $\frac{|measured-exact|}{exact} *100%$ . We know that the exact value is 80 because the buyer was supposed to given 80. 75 is the measured value because that was what the buyer was given.