How do i solve this (Tamgent Segment)

Mathematics

1 answer:

fgiga [73]3 years ago

4 0

Answer:

Step-by-step explanation:

Since DE is tangent to the circle, that means DE is perpendicular to EF

==> DF = sqrt(4^2+3^2) = 5

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$\textit{horizontal parabola vertex form with focus point distance} \\\\ 4p(x- h)=(y- k)^2 \qquad \begin{cases} \stackrel{vertex}{(h,k)}\qquad \stackrel{focus~point}{(h+p,k)}\qquad \stackrel{directrix}{x=h-p}\\\\ p=\textit{distance from vertex to }\\ \qquad \textit{ focus or directrix}\\\\ \stackrel{"p"~is~negative}{op ens~\supset}\qquad \stackrel{"p"~is~positive}{op ens~\subset} \end{cases} \\\\[-0.35em] \rule{34em}{0.25pt}$

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