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Minchanka [31]
3 years ago
12

How do i solve this (Tamgent Segment)​

Mathematics
1 answer:
fgiga [73]3 years ago
4 0

Answer:

5

Step-by-step explanation:

Since DE is tangent to the circle, that means DE is perpendicular to EF

==> DF = sqrt(4^2+3^2) = 5

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What is the surface area of a rectangular prism that has these dimensions? 2 cm x 3 cm x 5 cm?
algol [13]
30 centimeters cubed is the answer
8 0
3 years ago
Which answer best describes the complex zeros of the polynomial function?
marysya [2.9K]

<u>Answer-</u>

<em>D. The function has one real zero and two nonreal zeros. The graph of the function intersects the x-axis at exactly one location.</em>

<u>Solution-</u>

The given polynomial is,

f(x)=x^3-x^2+6x-6

The zeros of the polynomials are,

\Rightarrow f(x)=0

\Rightarrow x^3-x^2+6x-6=0

\Rightarrow x^2(x-1)+6(x-1)=0

\Rightarrow (x^2+6)(x-1)=0

\Rightarrow (x^2+6)=0,(x-1)=0

\Rightarrow x=\sqrt{-6},\ x=1

\Rightarrow x=1,\ \pm \sqrt6i

Therefore, this function has only one real zero i.e 1 and two nonreal zeros i.e ±√6i . The graph of the function intersects the x-axis at exactly one location i.e at x = 1

3 0
3 years ago
I need help with 3,4 6,7 8 9 and 10 please
lbvjy [14]

Answer:

Knowing others is intelligence; knowing yourself is true wisdom. mastering others is strength; mastering yourself is true power. if you realize that you have enough, you are truly rich, "And the cause of not following your heart, is in spending the rest of your life wishing you had."

3 0
2 years ago
What would be the steps in solving 2b + 3b = 3?
sweet-ann [11.9K]

The answer is b=\frac{3}{5}.

Let's solve your equation step-by-step.

2b+3b=3

Step 1: Simplify both sides of the equation.

2b+3b=3

(2b+3b)=3(Combine Like Terms)

5b=3

5b=3

Step 2: Divide both sides by 5.

5b/5=3/5

So, the answer is b=\frac{3}{5}.

4 0
3 years ago
(-2,3)(0,8) what is en equation for these points
jenyasd209 [6]

Answer:

The line equation that passes through the given points is          5x – 2y + 16 = 0

Explanation:

Given:

Two points are A(-2, 3) and B(0, 8).

To find:

The line equation that passes through the given two points.

Solution:

We know that, general equation of a line passing through two points (x1, y1), (x2, y2) is given by

\frac{(y- y1)}{(x-x_1)}= \frac{((y_2- y_1)}{(x_2- x_1 )}

{(y- y1)= \frac{((y_2- y_1)}{(x_2- x_1 )}\times(x-x_1).............(1)

here, in our problem x1 = 0, y1 = 8, x2 = -2 and y2 = 3.

Now substitute the values in (1)

y-8 = \frac{(3-8)}{(- 2 - 0)}\times(x- 0)

y-8 = \frac{(- 5)}{(-2)}\times(x)

y-8 =\frac{5}{2}x

2y – 16 = 5x

5x – 2y + 16 = 0

Hence, the line equation that passes through the given points is 5x – 2y + 16 = 0.

4 0
3 years ago
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