3 years ago

The function g(x) is graphed.

Mathematics

1 answer:

ASHA 777 [7]3 years ago

5 0

Answer:

I got A, B, D

Step-by-step explanation:

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620,000 rounded to the ten thousand

Trava [24]

Youre answer would be <span> 620,000 hope this helps!!!</span>

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4 years ago

Leon wrote an expression that is equivalent to (30 + 6) ÷ 12. Which expression could be the one Leon wrote?

lesya [120]

Answer:

36/3*4

Step-by-step explanation:

Brainliest please!

8 0

4 years ago

If tñ=2ñ+3, find S10

Allisa [31]

Answer:

$S_{10}=280$

Step-by-step explanation:

Given that,

$t_n=2n+3$ ...(1)

We need to find the value of $S_{10}$ .

Put n = 1 to find the first term.

$t_1=2(1)+3=5$

Put n = 2 to find the second term.

$t_2=2(2)+3=7$

Put n = 3 to find the third term.

$t_3=2(3)+3=9$

Put n = 10 to find the tenth term.

$t_{10}=2(10)+3=23$

It means we need to find the sum of 5,7,9,.....,23.

The formula for the sum of n terms is given by :

$S_=\dfrac{n}{2}(a+a_n)$

We have, n = 10, a = 5 and $a_n=23$

So,

$S=\dfrac{10}{2}(5+23)\\\\S_{10}=10\times 28\\\\=280$

So, the value of $S_{10}$ is equal to 280.

3 0

3 years ago

Which matrix equation has the solution

leonid [27]

Answer: x=0.6 btw how do you put a picture into a question.

5 0

3 years ago

You have 2,112 grams of a radioactive kind of mercury. How much will be left after 188 days if it's half-life is 47 days?

Anastasy [175]

Answer:

132 g

Step-by-step explanation:

Initial amount = 2112 g
Time = 188 days
Half-life = 47 days

188 days / 47 days = 4 periods

<u>Mercury left after 188 days:</u>

2112 * (1/2)^4 =
2112* 1/16 =
2112/16 =
132 g

4 0

3 years ago