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Lostsunrise [7]
3 years ago
15

Which matrix equation has the solution

Mathematics
1 answer:
leonid [27]3 years ago
5 0

Answer: x=0.6 btw how do you put a picture into a question.

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Can someone solve this for me please, i really need help
Aleksandr [31]

Answer:

I sorted them by colors: red goes with red, blue with blue, purple with purple and brown with brown :))

Step-by-step explanation:

5 0
3 years ago
Check whether 7+3x is a factor of 3x^3+7x
BartSMP [9]

Answer:

no

Step-by-step explanation:

refer to picture for solution

3 0
3 years ago
A bicycle store costs ​$2250 per month to operate. The store pays an average of ​$40 per bike. The average selling price of each
lesantik [10]

Answer:

75

Step-by-step explanation:

Given That :

Operation cost = $2250 per month

Purchase price per bike = $40

Average selling price per bike = $70

How many bicycles must the store sell each month to break even ;

Break even point = point at which there is net profit / loss = 0

Let number of bicycles store must sell = x

Operation cost + (purchase price * Number of bicycles) = selling price * Number of bicycles

2250 + 40x = 70x

2250 = 70x - 40x

2250 = 30x

x = 2250 / 30

x = 75

To break even 75 bicycles must be sold

5 0
3 years ago
Find the Net Pay: 40 hours worked, $7.85 an hour. Deductions: Federal tax $32.24, Social Security $24.02, Other $24.53 Answer $3
Trava [24]
For the answer to the question on what is the net pay if you are <span>40 hours worked, $7.85 an hour. Deductions: Federal tax $32.24, Social Security $24.02, Other.

The answer to this question is the last one which is </span><span>$233.21

I hope my answer helped you.</span>
6 0
3 years ago
Read 2 more answers
A researcher plants 22 seedlings. After one month, independent of the other seedlings, each seedling has a probability of 0.08 o
Andrews [41]

Answer:

E(X₁)= 1.76

E(X₂)= 4.18

E(X₃)= 9.24

E(X₄)= 6.82

a. P(X₁=3, X₂=4, X₃=6;0.08,0.19,0.42)= 0.00022

b. P(X₁=5, X₂=5, X₄=7;0.08,0.19,0.31)= 0.000001

c. P(X₁≤2) = 0.7442

Step-by-step explanation:

Hello!

So that you can easily resolve this problem first determine your experiment and it's variables. In this case, you have 22 seedlings (n) planted and observe what happens with the after one month, each seedling independent of the others and has each leads to success for exactly one of four categories with a fixed success probability per category. This is a multinomial experiment so I'll separate them in 4 different variables with the corresponding probability of success for each one of them:

X₁: "The seedling is dead" p₁: 0.08

X₂: "The seedling exhibits slow growth" p₂: 0.19

X₃: "The seedling exhibits medium growth" p₃: 0.42

X₄: "The seedling exhibits strong growth" p₄:0.31

To calculate the expected number for each category (k) you need to use the formula:

E(XE(X_{k}) = n_{k} * p_{k}

So

E(X₁)= n*p₁ = 22*0.08 = 1.76

E(X₂)= n*p₂ = 22*0.19 = 4.18

E(X₃)= n*p₃ = 22*0.42 = 9.24

E(X₄)= n*p₄ = 22*0.31 = 6.82

Next, to calculate each probability you just use the corresponding probability of success of each category:

Formula: P(X₁, X₂,..., Xk) = \frac{n!}{X_{1}!X_{2}!...X_{k}!} * p_{1}^{X_{1}} * p_{2}^{X_{2}} *.....*p_{k}^{X_{k}}

a.

P(X₁=3, X₂=4, X₃=6;0.08,0.19,0.42)= \frac{22!}{3!4!6!} * 0.08^{3} * 0.19^{4} * 0.42^{6}\\ = 0.00022

b.

P(X₁=5, X₂=5, X₄=7;0.08,0.19,0.31)= \frac{22!}{5!5!7!} * 0.08^{5} * 0.19^{5} * 0.31^{7}\\ = 0.000001

c.

P(X₁≤2) = \frac{22!}{0!} * 0.08^{0} * (0.92)^{22} + \frac{22!}{1!} * 0.08^{1} * (0.92)^{21} + \frac{22!}{2!} * 0.08^{2} * (0.92)^{20} = 0.7442

I hope you have a SUPER day!

8 0
3 years ago
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