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Nesterboy [21]
3 years ago
5

Need HELP ASAP!! Please help me

Mathematics
1 answer:
ivann1987 [24]3 years ago
7 0
Answer:
The length of the remaining piece of thread is 1/16
Step-by-step explanation:
Given:
A tailor cuts a piece of thread One-half of an inch long from a piece Nine-sixteenths of an inch long.
Now, to find the length of the remaining piece of thread.
Total thread = 9/16
Tailor cuts a piece of thread = 1/2
Now, to get the length of the remaining piece of thread by subtracting tailor cuts a piece of thread from the total thread:

9/16-1/2= 9-8/16 = 1/16
Therefore, the length of the remaining piece of thread is 1/16 :)
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The BlueSky Airlines has sold tickets for his plane to travel from Savannah to Atlanta. This plane carries 115 passengers. Howev
oee [108]

Answer:

it would be day 4 because if u add all of the tickets up once you get to day 5 it goes over 115

Step-by-step explanation:


8 0
3 years ago
60 pointssss!!!!! Need Help ASAP
Lerok [7]
Why Brainly capping
6 0
3 years ago
Calculate the volume of each diagrams.
wariber [46]

The volume of the solid objects are 612π in³ and 1566πcm³

<h3>Volume of solid object</h3>

The given objects are composite figures consisting of two shapes.

The volume of the blue figure is expressed as;

Volume = Volume of cylinder + volume of hemisphere

Volume = πr²h + 2/3πr³

Volume =  πr²(h + 2/3r)

Volume =  π(6)²(13+2/3(6))

Volume = 36π(13 + 4)

Volume = 612π in³

For the other object

Volume = Volume of cylinder + volume of cone

Volume = πr²h + 1/3πr²h

Volume =  π(9)²(15) + 1/3π(9)²(13)

Volume=  81π (15+13/3)
Volume= 1566πcm³

Hence the volume of the solid objects are 612π in³ and 1566πcm³

Learn more on volume of composite figures here: brainly.com/question/1205683

#SPJ1

8 0
2 years ago
Please help me! worth 35 points!
Debora [2.8K]

Answer:

1. 72, 2. 36, 3. 80, 4. 54

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
together,sarah's two cats have the same mass as her dog,11 kg.the mass of one cat is 1500 g greater than the mass of the other.
Alika [10]
Let (a) be the first cat
let (b) be the second cat
a +b=11kg-----(1)
a=b+1500g⇒(1.5 kg)-------(2)
so now u have a system of two unknowns
a=11-b
substitute a in (2)
11-b=b+1.5
11-1.5=2b
2b=9.5
b=9.5/2=4.75
subs. b in (1)
a+b=11
a+4.75=11
a=11-4.75=6.25
so cat (a) is 6.25 kg
and (b) is 4.75 kg
hope I helped



6 0
3 years ago
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