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max2010maxim [7]
1 year ago
5

Callie is installing a rectangular walkway up to her house. The width of the walkway is 5 feet and the length is 27 feet. She ne

eds to calculate the area of the walkway to determine the amount of materials needed to build it.
Mathematics
1 answer:
Sergio [31]1 year ago
4 0

Answer:

I hate my life I hate my life I hate my life

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3. The picture below shows a relationship between the number of circles and triangles.
dimaraw [331]

Answer:

D or A

Step-by-step explanation:

(D) One circle : four triangles  

  Example:

One triangle is 1/4 of a circle

(A) One circle : four triangles

    Example:

If there is two circles, the triangles will double like it shows [evidences]

6 0
3 years ago
Which of these is equal to cos 47°?
tigry1 [53]
C tan 43 I think it right
4 0
3 years ago
Read 2 more answers
Jonah calculates that the perimeter of the rectangle below is 6 1/4x - 3. Explain his error and include the correct expression.
Natalka [10]

Answer:

Jonah left out the other two sides!

3 0
2 years ago
In a study of 300 randomly selected
7nadin3 [17]
I would say A because you would expect that less than half of them are out of state as more then half in the study are in state.
5 0
2 years ago
Soap films and bubbles are colorful because the interference conditions depend on the angle of illumination (which we aren't cov
mylen [45]

Answer:

56.39 nm

Step-by-step explanation:

In order to have constructive interference total optical path difference should be an integral number of wavelengths (crest and crest should be interfered). Therefore the constructive interference condition for soap film can be written as,

2t=(m+\frac{1}{2} ).\frac{\lambda}{n}

where λ is the wavelength of light and n is the refractive index of soap film, t is the thickness of the film, and m=0,1,2 ...

Please note that here we include an additional 1/2λ phase shift due to reflection from air-soap interface, because refractive index of latter is higher.

In order to have its longest constructive reflection at the red end (700 nm)

t_1=(m+\frac{1}{2} ).\frac{\lambda}{2.n}\\ \\ t_1=\frac{1}{2} .\frac{700}{(2)*(1.33)}\\ \\ t_1=131.58\ nm

Here we take m=0.

Similarly for the constructive reflection at the blue end (400 nm)

t_2=(m+\frac{1}{2} ).\frac{\lambda}{2.n}\\ \\ t_2=\frac{1}{2} .\frac{400}{(2)*(1.33)}\\ \\ t_2=75.19\ nm

Hence the thickness difference should be

t_1-t_2=131.58-75.19=56.39 \ nm

7 0
2 years ago
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