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maxonik [38]
2 years ago
14

Jim and Sean went to the diner and bought two egg scrambles. Jim also got a cup of coffee for a dollar. If their total bill was

$9.50, how much was each egg scramble?
LET X = 9.5

EQUATION:
Mathematics
1 answer:
Alex73 [517]2 years ago
4 0

Answer:

If only Jim purchased a cup of coffee, we will subtract its cost from the total;

9.50 - 1.00 = 8.50

Assuming that the two purchased nothing else for breakfast, and that the cost of an egg scramble was the same for both, let's call the price of the egg scramble x.

Since they both bought eggs, then 2x = 8.50

x = $4.25, the price for each egg scramble

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An area is approximated to be 14 in 2 using a left-endpoint rectangle approximation method. A right- endpoint approximation of t
USPshnik [31]
The trapezoidal approximation will be the average of the left- and right-endpoint approximations.

Let's consider a simple example of estimating the value of a general definite integral,

\displaystyle\int_a^bf(x)\,\mathrm dx

Split up the interval [a,b] into n equal subintervals,

[x_0,x_1]\cup[x_1,x_2]\cup\cdots\cup[x_{n-2},x_{n-1}]\cup[x_{n-1},x_n]

where a=x_0 and b=x_n. Each subinterval has measure (width) \dfrac{a-b}n.

Now denote the left- and right-endpoint approximations by L and R, respectively. The left-endpoint approximation consists of rectangles whose heights are determined by the left-endpoints of each subinterval. These are \{x_0,x_1,\cdots,x_{n-1}\}. Meanwhile, the right-endpoint approximation involves rectangles with heights determined by the right endpoints, \{x_1,x_2,\cdots,x_n\}.

So, you have

L=\dfrac{b-a}n\left(f(x_0)+f(x_1)+\cdots+f(x_{n-2})+f(x_{n-1})\right)
R=\dfrac{b-a}n\left(f(x_1)+f(x_2)+\cdots+f(x_{n-1})+f(x_n)\right)

Now let T denote the trapezoidal approximation. The area of each trapezoidal subdivision is given by the product of each subinterval's width and the average of the heights given by the endpoints of each subinterval. That is,

T=\dfrac{b-a}n\left(\dfrac{f(x_0)+f(x_1)}2+\dfrac{f(x_1)+f(x_2)}2+\cdots+\dfrac{f(x_{n-2})+f(x_{n-1})}2+\dfrac{f(x_{n-1})+f(x_n)}2\right)

Factoring out \dfrac12 and regrouping the terms, you have

T=\dfrac{b-a}{2n}\left((f(x_0)+f(x_1)+\cdots+f(x_{n-2})+f(x_{n-1}))+(f(x_1)+f(x_2)+\cdots+f(x_{n-1})+f(x_n))\right)

which is equivalent to

T=\dfrac12\left(L+R)

and is the average of L and R.

So the trapezoidal approximation for your problem should be \dfrac{14+21}2=\dfrac{35}2=17.5\text{ in}^2
4 0
2 years ago
A rectangle prism is shown below. What is the volume of the prism?
8_murik_8 [283]
I can help with the formula just do the math on a calculator you multiply length x width x height
8 0
2 years ago
Forever 21 has a student discount of 7%. The total for your items is $24 what is your total after the discount?
Ksju [112]

Answer:

the answer is $22.32

Step-by-step explanation:

8 0
3 years ago
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17. Find m2 USW if m_ USW = 7x - 34 and m2 TSR = 4x + 29.​
SVEN [57.7K]

Answer:

Step-by-step explanation:

Find the diagram attached. From the diagram, we can see that;

<USW = <TSR (vertically opposite angles)

Given

<USW = 7x-34

<TSR = 4x+29

Equate

7x-34 = 4x+29

7x-4x = 29+34

3x = 63

x = 63/3

x = 21°

Find <USW

<USW =7x-34

<USW =7(21)-34

<USW = 147-34

<USW = 113°

Hence the measure of <USW is 113°

5 0
3 years ago
The Stomping Elephants volleyball team plays 30 matches in a week-long tournament. On average, they win 4 out of every 6 matches
8_murik_8 [283]

Answer:

The mean for the number of matches that they win in the tournament is 20.

Step-by-step explanation:

For each match, there are only two possible outcomes. Either they win, or they do not. The probability of winning a match is independent from other matches. So we use the binomial probability distribution to solve this problem.

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

The expected value of the binomial distribution is:

E(X) = np

The Stomping Elephants volleyball team plays 30 matches in a week-long tournament.

This means that n = 30

On average, they win 4 out of every 6 matches.

This means that p = \frac{4}{6} = \frac{2}{3}

What is the mean for the number of matches that they win in the tournament?

E(X) = np = 30\frac{2}{3} = 20

The mean for the number of matches that they win in the tournament is 20.

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