Functions quiz on khan. G(-4)=
1 answer:
You might be interested in
Look at the picture.
1)|AM| = |MB| = x
|AN| = |NC| = y
|BC| = 2y - 2x = 2(y - x)
|MN| = y - x
Therefore |BC| = 2|MN|
2)|AM| = |MB| = x
|AN| = |NC| = y
|BC| = 2y - 2x = 2(y - x)
|MN| = y - x
Therefore |BC| = 2|MN|
1)|AM| = |MB| = x
|AN| = |NC| = y
|BC| = 2y - 2x = 2(y - x)
|MN| = y - x
Therefore |BC| = 2|MN|
2)|AM| = |MB| = x
|AN| = |NC| = y
|BC| = 2y - 2x = 2(y - x)
|MN| = y - x
Therefore |BC| = 2|MN|
Answer:
3√3 units
Step-by-step explanation:
We are asked to find the altitude of the equilateral triangle whose perimeter is 18 . Firstly let us find the side of the∆.
Now we know that in a equilateral triangle , the altitude of the triangle with side length a is ,
Plug in the value of a that is 6 , we will get ,