1 and 1/2x+3/4x=5/8
combine x's
1 and 1/2x=4/4x+2/4x=6/4x
6/4x+3/4x=5/8=9/4x
9/4x=5/8
multiply both sides by 8
18x=5
x=5/18
x=5/18 or aprox 0.277777777777
A.
B and C are wrong because x is more than or equal to 3.
D is wrong because y is the weight of oranges and cannot be negative.
Three million, one hundred and fifty two thousand, three hundred and eight.
<em>5 to the 2nd power times 5 to the 2nd power is equivalent to 625</em>
<h2>
Explanation:</h2>
In this case, we have the following statement:
<em>5 to the 2nd power times 5 to the 2nd power. </em>In a mathematical language:
From product rules, we know that:
Applying this rule to our problem:
<em>5 to the 2nd power times 5 to the 2nd power is equivalent to 625</em>
<h2>
Learn more:</h2>
Rules of exponents: brainly.com/question/12140557
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Hello!
Here are some rules to determine the number of significant figures.
- Numbers that are not zero are significant (45 - all are sigfigs)
- Zeros between non-zero digits are significant (3006 → all are sigfigs)
- Trailing zeros are not significant (0.067 → the first two zeros are not sigfigs)
- Trailing zeros after a decimal point are always significant (1.000 → all are sigfigs)
- Trailing zeros in a whole number are not significant (7800 → the last two zeros are not sigfigs)
- In scientific notation, the exponential digits are not significant, known as place holders (6.02 x 10² → 10² is not a sigfig)
Now, let's find the number of significant figures in each given number.
A). 296.54
Since these digits are all <em>non-zero</em>, there are 5 significant figures.
B). 5003.1
Since the two <em>zeros are between non-zero digits</em>, they are significant figures. Thus, there are 5 significant figures.
C). 360.01
Again, the two zeros are between non-zero digits. There are 5 significant figures.
D). 18.3
All of these digits are non-zero, hence, there are 3 significant figures.
Therefore, expression D has the fewest number of significant figures being 3.
