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diamong [38]
3 years ago
9

A conjecture and the two-column proof used to prove the conjecture are shown.

Mathematics
1 answer:
Ahat [919]3 years ago
4 0

Answer:

Just took the quiz hopefully this helps!

Step-by-step explanation:

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Please answer the problem and show your work.Thank you.
Vinvika [58]

Answer:

8. m=6

9.  x=2; Alyssa is incorrect because she subtracted 8 from 16 when in reality she should have divided 16 by 8 to get 2. The real solution is 2 because 8 times 2 is equal to 16.

Step-by-step explanation:

Question 8:

2m-6=m

-2m    -2m     (subtract 2m from both sides)

<u>-6</u>=<u>-m</u>  

-       -     (divide both sides by the negative)

m=6

Question 9:

<u>8x</u>=<u>16  </u>              (divide both sides of the equation by 8)

8     8

x=2

8 0
1 year ago
Read 2 more answers
On a coordinate plane, parallelogram A B C D has points (3, 6), (6, 5), (5, 1), and (2, 2).
jeka94

Answer:

  13 square units

Step-by-step explanation:

The bounding rectangle is 4 units wide and 5 units high, so has an area of 4×5 = 20 square units. From that are subtracted the areas of 4 triangles. 2 of them are 3 wide and 1 high, so have a combined area of 3×1 = 3 square units. The other two are 1 wide and 4 high, so have a combined area of 1×4 = 4 square units.

Then the area of the parallelogram is ...

  20 -3 -4 = 13 . . . . square units

3 0
3 years ago
How to re arrange 6x+2y=3 to y= mx+b form
Alex

Answer:

y=-3x+3/2

Step-by-step explanation:

move 6x to the other side

2y=-6x+3

then divide y

y=-3x+3/2

8 0
3 years ago
there are 2000 sheets of paper in 4 reams of paper.which of the following expresses the ratio of reams to paper?
antoniya [11.8K]
 -4:2000

 -2:1000

 -1:500

Hope this helped☺☺
4 0
3 years ago
Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used.
astra-53 [7]

Answer:

3\pi \rightarrow y=2\cos \dfrac{2x}{3}\\ \\\dfrac{2\pi }{3}\rightarrow y=6\sin 3x\\ \\\dfrac{\pi }{3}\rightarrow  y=-3\tan 3x\\ \\10\pi \rightarrow y=-\dfrac{2}{3}\sec \dfrac{x}{5}

Step-by-step explanation:

The period of the functions y=a\cos(bx+c) , y=a\sin(bx+c), y=a\sec (bx+c) or y=a\csc(bx+c) can be calculated as

T=\dfrac{2\pi}{b}

The period of the functions y=a\tan(bx+c) or y=a\cot(bx+c) can be calculated as

T=\dfrac{\pi}{b}

A. The period of the function y=-3\tan 3x is

T=\dfrac{\pi}{3}

B. The period of the function y=6\sin 3x is

T=\dfrac{2\pi}{3}

C. The period of the function y=-4\cot \dfrac{x}{4} is

T=\dfrac{\pi}{\frac{1}{4}}=4\pi

D. The period of the function y=2\cos \dfrac{2x}{3} is

T=\dfrac{2\pi}{\frac{2}{3}}=3\pi

E. The period of the function y=-\dfrac{2}{3}\sec \dfrac{x}{5} is

T=\dfrac{2\pi}{\frac{1}{5}}=10\pi

5 0
4 years ago
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