3 years ago

Find the area of the composite figure.

Mathematics

2 answers:

forsale [732]3 years ago

8 0

Answer:

I think B but not so sure

<h2> Hoping you have a good day</h2>

satela [25.4K]3 years ago

5 0

Answer:

Step-by-step explanation:

radius of semi circle=8/2=4 in

height of triangle=14-4=10 in.

area of composite figure=1/2×8×10+π×4²=40+16 π≈90.3 sq. in

You might be interested in

CAN SOMEONE PLEASE HELP ME???<br> ↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓∵

nata0808 [166]

Answer:

it is number 3 (-1/5)

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Find the value of the variable.

Alinara [238K]

Answer:

x = 25√2, y = 25

Step-by-step explanation:

x = 25(√2) = 25√2

y = 25

8 0

3 years ago

Read 2 more answers

In a class of 50 students, everyone has either a pierced nose or a pierced ear. The professor asks everyone with a pierced nose

Tems11 [23]

Answer: 3

Step-by-step explanation:

Let E be the event of that student pierces ear and N be the event of that student pierces nose.

Given: $n(E\cup N=50)$

$n(E)=46\\\\n(N)=7$

For any two event A and B, we have

$n(A\cup B)=n(A)+n(B)-n(A\cap B)$

Similarly , $n(E\cup N)=n(E)+n(N)-n(E\cap N)$

$50=46+7-n(E\cap N)\\\\\Rightarrow\ n(E\cap N)=53-50=3$

Hence, 3 students have piercings both on their ears and their noses.

7 0

3 years ago

The total weight of 9 bags of potatoes is 36 kilograms. Each bag weighs the same amount. What is the weight, in grams, of each b

Sunny_sXe [5.5K]

Answer:

4000 grams

Step-by-step explanation:

8 0

3 years ago

Find an explicit rule for the nth term of a geometric sequence where the second and fifth terms are -6 and 162, respectively. Pl

kicyunya [14]

Hello,

$u_{0} =a\\
 u_{1} =a*r\\
 u_{2} =a*r^{2}=-6\\
 u_{3} =a*r^{3}\\
 u_{4} =a*r^{4}\\
 u_{5} =a*r^{5}=162\\
....\\
\boxed{ u_{n} =a*r^{n}} \\

\dfrac{ 162}{-6} = \dfrac{ u_{5} }{ u_{3}} = \dfrac{ a*r^{5}}{ a*r^{2}} =r^3= -27\\
==\ \textgreater \ r=-3\\

 u_{2} =a*r^{2}=-6=a*(-3)^2 \ ==\ \textgreater \ a=-\frac{6}{9} =-\frac{2}{3}\\


\boxed{ u_{n} =-\frac{2}{3}*(-3)^{n}=(-1)^{n+1}*2*3^{n-1}} \\

$

8 0

4 years ago

Read 2 more answers