<h3><u>Question:</u></h3>
Juan and raj cut up a banana to put on cereal. juan puts 1/7 of the banana on his bowl of cereal, and raj puts 2/5 of the banana on his bowl of cereal.
what fraction of the banana did juan and raj put on their cereal altogether?
a. 2/35 banana
b. 3/12 banana
c. 3/7 banana
d. 19/35 banana
<h3><u>Answer:</u></h3>
Juan and Raj altogether put 19/35 banana
<h3><u>Solution</u>:</h3>
Given that, Juan and Raj cut up a banana to put on cereal
We have to find the fraction of banana put by Juan and Raj altogether
This means, we have to add both the fractions
Thus they put 
of banana by Juan and Raj altogether
Answer:
I’m not sure :/
Step-by-step explanation:
Answer:
0.070
Step-by-step explanation:
Y = number on trial
Y has a negative binomial distribution
r = 3
P = 30% = 0.3 probability of positive indication.
P(Y = 11) probability of 11 employees that must be tested to get 3 positives
Y-1Cr-1*p^r*q^(y-r)
Y-1 = 11-1 = 10
r-1 = 3 -1 = 2
10C2 x 0.3³x0.7⁸
45x0.027x0.05764801
= 0.070
This is the probability that 11 employees must be tested to get 3 positives.
Answer: 3.6cm
Step-by-step explanation:
Using the volume formula; solve for a;
![a^2=\frac{V}{h}\\ a=\sqrt[]{\frac{V}{h} }](https://tex.z-dn.net/?f=a%5E2%3D%5Cfrac%7BV%7D%7Bh%7D%5C%5C%20a%3D%5Csqrt%5B%5D%7B%5Cfrac%7BV%7D%7Bh%7D%20%7D)
![a=\sqrt[]{\frac{104cm^3}{8cm} }](https://tex.z-dn.net/?f=a%3D%5Csqrt%5B%5D%7B%5Cfrac%7B104cm%5E3%7D%7B8cm%7D%20%7D)
![a=\sqrt[]{13cm^2}](https://tex.z-dn.net/?f=a%3D%5Csqrt%5B%5D%7B13cm%5E2%7D)
Answer:
–9xy2 – 6x2y + 5x3
–9xy2 – 6x2y – 5x3
9xy2 + 6x2y + 5x3
9xy2 – 6x2y + 5x3
the answer is 9xy2 – 6x2y + 5x3
Step-by-step explanation:
