3 years ago

HELP ME I BEG OF YOU!!!!

Mathematics

2 answers:

xxMikexx [17]3 years ago

6 0

Answer:

The correct answer is A

Step-by-step explanation:

Vladimir [108]3 years ago

4 0

Answer:

B) -34.5 < x

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Hope this helps!

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5.3N + 7.25 = 70.85 what is N

Leviafan [203]

N= 12

Subtract 70.85 and 7.25 which equals 63.6. Then take 63.6 divided by 5.3 and it equals 12! Hope this helps.

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3 years ago

A ball is thrown upward with an initial velocity of 60 mph. it is thrown from a height of 5 feet. what is the maximum height it

natima [27]

Answer:

h = 61.25 m

Step-by-step explanation:

It is given that,

The initial velocity of the ball, v = 60 m/s

It is thrown from a height of 5 feet, $h_o=5\ ft$

We need to find the maximum height it reaches. The height reached by the projectile as a function of time t is given by :

$h=-16t^2+vt+h_0$

Putting all the values,

$h=-16t^2+60t+5$ .....(1)

For maximum height, put

$\dfrac{dh}{dt}=0\\\\\dfrac{-16t^2+60t+5}{dt}=0\\\\-32t+60=0\\\\t=\dfrac{-60}{-32}\\\\t=1.875\ s$

Put t = 1.875 in equation (1)

$h=-16(1.875)^2+60(1.875)+5\\\\h=61.25\ m$

So, the maximum height reached by the ball is 61.25 m.

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3 years ago

Please help I really need help please ans thank you

Vinil7 [7]

Answer:

see below

Step-by-step explanation:

x = 63 and y = 27

180 - 117 Gives 63

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