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3 years ago

Which of the following characteristics of the set {(0 , 8), (8 , 0), (1 , 6), (6 , 1), (2 , 4), (4 , 2)} make it a function?

Mathematics

1 answer:

photoshop1234 [79]3 years ago

6 0

Answer:

Step-by-step explanation:

For a relation to be a function, the ordered pairs do not repeat any of the x values. This is Answer C.

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Select all expressions that are equivalent to 10q + 5 ?

OLga [1]

Answer:

5q + 5q + 5

2q + 5 + 8q

5(2q + 1)

Step-by-step explanation:

5 0

3 years ago

Find the area enclosed by the figure. Use 3.14 for π. (The figure is not to scale).

gtnhenbr [62]

Answer:

97.27 yd²

Step-by-step explanation:

First let's find the area of the right triangle on the left side. To do that, multiply 6x5, then divide the product by 2, since a right triangle is half a rectangle.

6x5=30

30/2=15

Area of triangle=15 yd²

Find area of the middle rectangle. So multiply the length by the width.

9x6=54

Area of rectangle=54 yd²

Find area of the half circle. Formula for area of circle is $A=\pi r^{2}$ . Pi is about 3.14, and radius ( $r$ ) is 3. Radius is half of the diameter of circle, and the 6 on the left says the diameter of circle.

$\pi$ x $3^{2}$ ≈28.27

Area of circle is about 28.27 yd²

Add up the three areas.

15+54+28.27=97.27

3 0

3 years ago

Read 2 more answers

25 points will mark branliest!!!

Irina18 [472]

B. its 1/2 of the original volume, because the pyramid is doubled the height and, the length and width are cut in half. It would equal 1/2 the volume of the original pyramid.

3 0

4 years ago

Read 2 more answers

Find T5(x) : Taylor polynomial of degree 5 of the function f(x)=cos(x) at a=0 . (You need to enter function.) T5(x)= Find all va

Burka [1]

Answer:

$\bf cos(x)\approx1-\displaystyle\frac{x^2}{2}+\displaystyle\frac{x^4}{4!}=\\\\=1-\displaystyle\frac{x^2}{2}+\displaystyle\frac{x^4}{24}$

The polynomial is an approximation with an error less than or equals to 0.002652 for x in the interval

[-1.113826815, 1.113826815]

Step-by-step explanation:

According to Taylor's theorem

$\bf f(x)=f(0)+f'(0)x+f''(0)\displaystyle\frac{x^2}{2}+f^{(3)}(0)\displaystyle\frac{x^3}{3!}+f^{(4)}(0)\displaystyle\frac{x^4}{4!}+f^{(5)}(0)\displaystyle\frac{x^5}{5!}+R_6(x)$

with

$\bf R_6(x)=f^{(6)}(c)\displaystyle\frac{x^6}{6!}$

for some c in the interval (-x, x)

In the particular case f

f(x)=cos(x)

we have

$\bf f'(x)=-sin(x)\\f''(x)=-cos(x)\\f^{(3)}(x)=sin(x)\\f^{(4)}(x)=cos(x)\\f^{(5)}(x)=-sin(x)\\f^{(6)}(x)=-cos(x)$

therefore

$\bf f'(x)=-sin(0)=0\\f''(0)=-cos(0)=-1\\f^{(3)}(0)=sin(0)=0\\f^{(4)}(0)=cos(0)=1\\f^{(5)}(0)=-sin(0)=0$

and the polynomial approximation of T5(x) of cos(x) would be

$\bf cos(x)\approx1-\displaystyle\frac{x^2}{2}+\displaystyle\frac{x^4}{4!}=\\\\=1-\displaystyle\frac{x^2}{2}+\displaystyle\frac{x^4}{24}$

In order to find all the values of x for which this approximation is within 0.002652 of the right answer, we notice that

$\bf R_6(x)=-cos(c)\displaystyle\frac{x^6}{6!}$

for some c in (-x,x). So

$\bf |R_6(x)|\leq|\displaystyle\frac{x^6}{6!}|=\displaystyle\frac{|x|^6}{6!}$

and we must find the values of x for which

$\bf \displaystyle\frac{|x|^6}{6!}\leq0.002652$

Working this inequality out, we find

$\bf \displaystyle\frac{|x|^6}{6!}\leq0.002652\Rightarrow |x|^6\leq1.90944\Rightarrow\\\\\Rightarrow |x|\leq\sqrt[6]{1.90944}\Rightarrow |x|\leq1.113826815$

Therefore the polynomial is an approximation with an error less than or equals to 0.002652 for x in the interval

[-1.113826815, 1.113826815]

8 0

3 years ago

What is the domain of function of f(x)=-2x+4x

dem82 [27]

Answer:

Domain= x∉Real numbers

Step-by-step explanation:

4 0

3 years ago