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nadya68 [22]
3 years ago
15

PLZZZ HELP I WILL GIVE BRAINLEST ON A TIMER

Mathematics
2 answers:
Agata [3.3K]3 years ago
4 0

Answer:

X coordinate is between 2 and 3

Y coordinate is between 2 and 3 as well.

Step-by-step explanation:

Here's the proof! (Also, the other person is correct on this question as well.) Hope this helps! =w=

alex41 [277]3 years ago
3 0

Answer:

The x-coordinate is between 2 and 3, the y-coordinate is between 2 and 3 as well. Hope this helps :)

Step-by-step explanation:

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A discuss moves from P1 (4,8) to P2 (15,17). What is the lincar displacement in the horizontal and vertical directions? What is
Yakvenalex [24]

Answer:

The horizontal displacement is 11 units, the vertical displacement is 9 units, and the projection angle is 39.3 degrees.

Step-by-step explanation:

We can start using the definition of displacement in one dimension between any 2 points which is the difference between them, so we have

\Delta s = s_2-s_1

And apply it to get the horizontal and vertical displacements.

Once we have found them, we can use trigonometric functions to find the projection angle with respect the horizontal.

Linear displacements.

Using the definition of displacement, we can write the horizontal displacement as

\Delta x = x_2-x_1

So we can use the given points P1:(x_1,y_2)  \text{  and  } P_2: (x_2,y_2) on the displacement formula

\Delta x = 15-4\\\Delta x = 11

In the same manner we can look at the y components of those points to find the vertical displacement

\Delta y = 17-8\\\Delta y =9

Thus the horizontal displacement is 11 units and the vertical displacement is 9 units.

Projection angle.

The projection angle with respect the horizontal is the angle that is made between the line that connects the points P1 and P2 and the horizontal, so we can use the linear displacements previously found to write

\tan(\theta) = \cfrac{\Delta y}{\Delta x}

Solving for the angle we get

\theta = \tan^{-1}\left(\cfrac{\Delta y}{\Delta x}\right)

Replacing values

\theta = \tan^{-1}\left(\cfrac{9}{11}\right)

Which give us

\theta = 39.3^\circ

So the projection angle is 39.3 degrees.

7 0
3 years ago
**IF ANYONE CAN DO ALL OF THESE QUESTIONS CORRECTLY AND FAST, YOU WILK BE MARKED BRAINLIEST!!**What is the measure of arc BC?
bixtya [17]

I think the answer is BC= (bc + de)/2

7 0
3 years ago
What equation represents a line that when if graphed, passes through the points (0, -1) and
Keith_Richards [23]
Y= 2x-1
Explanation: First, you find slope. If the first point it x-axis point is 0 and the second x-axis point is 1 then you already know the answer is over 1, so you have to figure out how many up you are going on the y-axis from -1 to 1. Which is 2, so your slope is 2/1 or just 2. Next, you find your y-intercept, which is where the line crosses the y-axis, and the easy way to find this is finding what y is equal to when x is equal to 0, in the problem you are told (0, -1) as a point, so they gave you your y-intercept right there, which is -1. Finally you right the equation in slip intercept form (y= mx+b) which is y= 2x-1
5 0
3 years ago
What is the equation of a circle with center (−8, 3) and radius 8?
Genrish500 [490]

Answer:

x^2 + y^2 + 16x + 6y + 9 = 0

Step-by-step explanation:

Using the formula for equation of a circle

(x - a)^2 + (y + b)^2 = r^2

(a, b) - the center

r - radius of the circle

Inserting the values given in the question

(-8,3) and r = 8

a - -8

b - 3

r - 8

[ x -(-8)]^2 + (y+3)^2 = 8^2

(x + 8)^2 + (y + 3)^2 = 8^2

Solving the brackets

( x + 8)(x + 8) + (y +3)(y+3) = 64

x^2 + 16x + 64 + y^2 + 6y + 9 = 64

Rearranging algebrally,.

x^2 + y^2 + 16x + 6y + 9+64 - 64 = 0

Bringing in 64, thereby changing the + sign to -

Therefore, the equation of the circle =

x^2 + y^2 + 16x + 6y + 9 = 0

7 0
3 years ago
A train traveled 210 miles and 3.5 hours to its first stop. It then continued on traveling another 130 miles in 2.5 hours. 2hat
SpyIntel [72]

Answer:

56.7 ​mi/h.

Step-by-step explanation:

I took the test

6 0
3 years ago
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