All categories

3 years ago

Help please ! order the side lengths GH , HI , IG from least to greatest

Mathematics

1 answer:

jok3333 [9.3K]3 years ago

7 0

Answer:

IH < IG < HG

Step-by-step explanation:

To solve this equation remember that angle measurements correspond with sides. So, the largest angle will be opposite of the longest side and the smallest angle will be opposite of the shortest side.

First, you need to find m<I; do this by subtracting 52 and 45 from 180. This means that m<I=83, making it the largest angle. Therefore, the angles, in order of least to greatest, are <G, <H, <I. So, to find the final answer, find the sides opposite of each of the angles. This means the answer is IH < IG < HG.

You might be interested in

This is easy but I’m just too dumb

tangare [24]

You see how the a increases by 4 whenever b increases by one?

So, the equation is a=4b

Hope this helps!

5 0

3 years ago

Coach Shaw is buying baseball equipment for his team. He gets a reduced rate if he buys 8 baseballs for every 3 batting helmets.

Natalija [7]

Answer:

Helmets-12

Baseballs-32

Step-by-step explanation:

Given the tax rate as 6% and the reduced prices as $2.25/baseball and $22.50/helmet and that the budget is $400:

The new prices are reduced price plus tax:

$Baseball \ Price =2.25\times (1.06\%)=2.39\\\\Helmet \ Price= 22.50\times (1.06\%)=23.85$

Let x be the number of groups of 8 baseballs as well as the number of groups of 3 helmets,therefore:

$8x(2.39)+3x(23.85)=400\\\\19.12x+71.55x=400\\\\x=4.4116\\\\x\approx 4$

Substitute for x=4 to find the highest number of baseballs and helmets:

Helmets=4x3=12

Baseball=4x8=32

#Price cost will be 12x23.85+32x2.39=362.68 (balance=37.32)

Hence, Shaw can buy 12 helmets and 32 baseballs and still remain with $37.32

3 0

3 years ago

SOLVING EACH SYSTEM BY ELIMINATION <br><br><br> x+3y=5 x=-6y+14<br><br><br> HELP

nata0808 [166]

Answer:

$\mathrm{The\:solutions\:to\:the\:system\:of\:equations\:are:}$

$x=-4,\:y=3$

Step-by-step explanation:

Given the system of the equations

$x+3y=5;\:x=-6y+14$

solving by elimination method

$\begin{bmatrix}x+3y=5\\ x=-6y+14\end{bmatrix}$

$\mathrm{Arrange\:equation\:variables\:for\:elimination}$

$\begin{bmatrix}x+3y=5\\ x+6y=14\end{bmatrix}$

$x+6y=14$

$-$

$\underline{x+3y=5}$

$3y=9$

$\begin{bmatrix}x+3y=5\\ 3y=9\end{bmatrix}$

solve $3y=9$ for $y$ :

$3y=9$

$\frac{3y}{3}=\frac{9}{3}$

$y=3$

$\mathrm{For\:}x+3y=5\mathrm{\:plug\:in\:}y=3$

Solve $x+3\cdot \:3=5$ for x:

$x+3\cdot \:3=5$

$x+9=5$

$x=-4$

Therefore,

$\mathrm{The\:solutions\:to\:the\:system\:of\:equations\:are:}$

$x=-4,\:y=3$

6 0

3 years ago

Complete the equation so that it has solutions of –5 and 7. x2 x = 0

Pavlova-9 [17]

The equation it has solutions of –5 and 7 is x^2-2x-37=0

We have equation

solutions of equation are –5 and 7.

We have to find complete the equation.

We have given that solutions of the equation are -5, 7.

The standard form of a quadratic equation.

<h3>What is the factor of the quadratic equation?</h3>

$(x -\alpha) (x- \beta)$

Where we have

$p = -(\alpha+\beta) and q = (\alpha\times \beta)$

So, roots are

$( x- (-5)) (x-7)$

$p = -( -5+7)$ , $q =(-5)(7).$

$p = -2 and q = -35.$

On substituting p and q in equation

$x^2+(-2)x-37=0$

$x^2-2x-37=0$

Therefore,x^2-2x-37=0 is the equation of solution -5,7.

To learn more about the quadratic factor visit:

brainly.com/question/472337

4 0

2 years ago

Read 2 more answers

Please help me, haha...

sashaice [31]

Yup the answer is C !!

3 0

3 years ago