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3 years ago

Help please ! order the side lengths GH , HI , IG from least to greatest

Mathematics

1 answer:

jok3333 [9.3K]3 years ago

7 0

Answer:

IH < IG < HG

Step-by-step explanation:

To solve this equation remember that angle measurements correspond with sides. So, the largest angle will be opposite of the longest side and the smallest angle will be opposite of the shortest side.

First, you need to find m<I; do this by subtracting 52 and 45 from 180. This means that m<I=83, making it the largest angle. Therefore, the angles, in order of least to greatest, are <G, <H, <I. So, to find the final answer, find the sides opposite of each of the angles. This means the answer is IH < IG < HG.

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Mashcka [7]

Answer:

$\cfrac{991\sqrt{2} }{80}$

Step-by-step explanation:

For a start simplify each of the roots:

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$\sqrt{50} =\sqrt{25*2} =5\sqrt{2}$
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$\sqrt{98} =\sqrt{49*2} =7\sqrt{2}$

Now simplify the expression in steps:

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$6\sqrt{2}-\cfrac{48}{5\sqrt{2} } -\cfrac{45}{8\sqrt{2} } +2*7\sqrt{2} =$

$6\sqrt{2}-\cfrac{48*8+45*5}{5*8\sqrt{2} } +14\sqrt{2} =$

$20\sqrt{2}-\cfrac{609}{40\sqrt{2} } =$

$20\sqrt{2}-\cfrac{609*\sqrt{2} }{40\sqrt{2} *\sqrt{2} } =$

$20\sqrt{2}-\cfrac{609\sqrt{2} }{40*2 } =$

$20\sqrt{2}-\cfrac{609\sqrt{2} }{80 } =$

$\sqrt{2} (20-7\cfrac{49}{80} )=$

$\sqrt{2} *12\cfrac{31}{80} =$

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3 0

2 years ago

Mark for review (Will be highlighted on the review page) 1. Solve this equation: 80 = 3y + 2y + 4 + 1.

saul85 [17]

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3 years ago

Maria bought three t-shirts at her favorite store t shirt paradise. she had a 25% of coupon and paid $45 in total.what was the o

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So, your final answer is $56.25

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4 years ago

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Ilia_Sergeevich [38]

Answer:

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