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3 years ago

1. 7 x ____ = 70

Mathematics

2 answers:

Naddika [18.5K]3 years ago

8 0

Answer:

1. 7×10=70

2. 86×10=860

3. 830=3 tens

5. 6 tens=960

6. 10×61=610

7. 830×10=8300

8. 1080= 8 tens

9. 61×10=610

10. 100×10=1000

11. 79×10=790

12. 0 tens= 3700

13. 340= 4 tens

14. 358×10=3580

Viefleur [7K]3 years ago

4 0

Answer:

Step-by-step explanation:

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What is 1/2 X (6 X 4)+3 + 2 Please show your work

exis [7]

Answer:

Step-by-step explanation:

Use PEMDAS:

P Parentheses first

E Exponents (ie Powers and Square Roots, etc.)

MD Multiplication and Division (left-to-right)

AS Addition and Subtraction (left-to-right)

$\dfrac{1}{2}\times\underbrace{(6\times4)}_{1}+3+2\\\\=\underbrace{\dfrac{1}{2}\times24}_{2}+3+2\\\\=12+3+2=17$

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3 years ago

After he finished breakfast, Mr. Edwards left for work at fifteen minutes after seven. what time is this? Use a.m. or p.m.

Alex Ar [27]

7:15 AM

it is 15 minutes after 7 so 7:00 + 0:15 = 7:15
also breakfast is eaten in the morning so AM is right

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3 years ago

Help me with this pls

ella [17]

Answer:

7:3

Step-by-step explanation:

Divide both sides by 4

3 0

3 years ago

· The list price of an article is 25% above the selling price and the cost

dem82 [27]

Answer:

p=25%

discount=25%

Step-by-step explanation:

Cost Price = 1.25 x - .4(1.25x)= 1.25x- .5x

Cost Price = .75x

S P = C+P

Profit = Selling price - Cost price

= x - 0.75x

=0.25x

the Profit is 25 %

Discount is 25 %

6 0

3 years ago

Which is the inverse of the function a(d)=5d-3? And use the definition of inverse functions to prove a(d) and a-1(d) are inverse

Drupady [299]

Answer:

$a'(d) = \frac{d}{5} + \frac{3}{5}$

$a(a'(d)) = a'(a(d)) = d$

Step-by-step explanation:

Given

$a(d) = 5d - 3$

Solving (a): Write as inverse function

$a(d) = 5d - 3$

Represent a(d) as y

$y = 5d - 3$

Swap positions of d and y

$d = 5y - 3$

Make y the subject

$5y = d + 3$

$y = \frac{d}{5} + \frac{3}{5}$

Replace y with a'(d)

$a'(d) = \frac{d}{5} + \frac{3}{5}$

Prove that a(d) and a'(d) are inverse functions

$a'(d) = \frac{d}{5} + \frac{3}{5}$ and $a(d) = 5d - 3$

To do this, we prove that:

$a(a'(d)) = a'(a(d)) = d$

Solving for $a(a'(d))$

$a(a'(d)) = a(\frac{d}{5} + \frac{3}{5})$

Substitute $\frac{d}{5} + \frac{3}{5}$ for d in $a(d) = 5d - 3$

$a(a'(d)) = 5(\frac{d}{5} + \frac{3}{5}) - 3$

$a(a'(d)) = \frac{5d}{5} + \frac{15}{5} - 3$

$a(a'(d)) = d + 3 - 3$

$a(a'(d)) = d$

Solving for: $a'(a(d))$

$a'(a(d)) = a'(5d - 3)$

Substitute 5d - 3 for d in $a'(d) = \frac{d}{5} + \frac{3}{5}$

$a'(a(d)) = \frac{5d - 3}{5} + \frac{3}{5}$

Add fractions

$a'(a(d)) = \frac{5d - 3+3}{5}$

$a'(a(d)) = \frac{5d}{5}$

$a'(a(d)) = d$

Hence:

$a(a'(d)) = a'(a(d)) = d$

7 0

2 years ago