#1: 214 tickets split 9 ways does not work out to an integer number. Nobody wants 2/3 of a ticket, right?
So the trick here is to determine the first multiple of 9 greater than 214.
Note that 214/9 = 23.8. No good. Not an integer.
Multiply 23 by 9; we get 207. Multiply 24 by 9; we get 216.
So, given that we have 214 tickets already, we need 2 more, to make 216.
Check: Is 216 divisible by 9 without a remainder? Yes. Then each of the 9 students will get 24 tickets.
The rest of the problems are somewhat similar to this one.
See whether you can do the next one, #2.
If you'd share your results, I'd be happy to comment on what you've done.
Answer:
$180
Step-by-step explanation:$10 per hour, so 10 is multiplied by 9
He gets paid 90 Dollars for one day of work so we would multiply that by Two days.
8/2.5
= 80/25
= 16/5
= 3 1/5
One sixth of an hour is 10 minutes.
That means it costs 5,700 every 10 minutes.
Costs 5,700 = 10 minutes
Dive 10 on both sides.
Costs 570 = 1 minute
Lets convert the minute into seconds.
Costs 570 = 60 seconds
Divide both sides by 60.
Costs 9.5 cents = 1 second
Round it off since you can't pay 9.5 cents.
Costs 10 cents = 1 second
This means that every second they pay 10 cents for the hotel. :D
Answer:
40
Step-by-step explanation:
f(4) = 3(4²) - 2(4)
= 3(16) - 8
= 48 - 8
= 40
when x=4, f(x) = 40
