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erma4kov [3.2K]
2 years ago
15

P(n)=n^2-5n; find p(-3)

Mathematics
1 answer:
ikadub [295]2 years ago
3 0

Answer:

p = -8

Step-by-step explanation:

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​ 6 38/45 + 2 5/9 ​<br><br> Enter your answer in the box as a mixed number in simplest form.
Paul [167]

Answer:

9 2/5

Step-by-step explanation:

6 38/45 + 2 5/9 ​

6 38/45 + 2 25/45 = 8 63/45 = 9 18/45 = 9 2/5

4 0
2 years ago
Help me out !?!??!?!l
Vlada [557]

Answer:67 is correct D

Step-by-step explanation:use parallel, so 71+x=180-42 x=67 67+71=138, 67= to your answer

4 0
2 years ago
Suppose that a spherical droplet of liquid evaporates at a rate that is proportional to its surface area: where V = volume (mm3
Alex

Answer:

V = 20.2969 mm^3 @ t = 10

r = 1.692 mm @ t = 10

Step-by-step explanation:

The solution to the first order ordinary differential equation:

\frac{dV}{dt} = -kA

Using Euler's method

\frac{dVi}{dt} = -k *4pi*r^2_{i} = -k *4pi*(\frac {3 V_{i} }{4pi})^(2/3)\\ V_{i+1} = V'_{i} *h + V_{i}    \\

Where initial droplet volume is:

V(0) = \frac{4pi}{3} * r(0)^3 =  \frac{4pi}{3} * 2.5^3 = 65.45 mm^3

Hence, the iterative solution will be as next:

  • i = 1, ti = 0, Vi = 65.45

V'_{i}  = -k *4pi*(\frac{3*65.45}{4pi})^(2/3)  = -6.283\\V_{i+1} = 65.45-6.283*0.25 = 63.88

  • i = 2, ti = 0.5, Vi = 63.88

V'_{i}  = -k *4pi*(\frac{3*63.88}{4pi})^(2/3)  = -6.182\\V_{i+1} = 63.88-6.182*0.25 = 62.33

  • i = 3, ti = 1, Vi = 62.33

V'_{i}  = -k *4pi*(\frac{3*62.33}{4pi})^(2/3)  = -6.082\\V_{i+1} = 62.33-6.082*0.25 = 60.813

We compute the next iterations in MATLAB (see attachment)

Volume @ t = 10 is = 20.2969

The droplet radius at t=10 mins

r(10) = (\frac{3*20.2969}{4pi})^(2/3) = 1.692 mm\\

The average change of droplet radius with time is:

Δr/Δt = \frac{r(10) - r(0)}{10-0} = \frac{1.692 - 2.5}{10} = -0.0808 mm/min

The value of the evaporation rate is close the value of k = 0.08 mm/min

Hence, the results are accurate and consistent!

5 0
3 years ago
There are 11.5 ounces of cereal in a container. Additional cereal is poured into the container at a rate of 2.25 ounces per seco
KatRina [158]

Answer:

13.........

Step-by-step explanation:


5 0
3 years ago
Please do this question
crimeas [40]
It would be 16 more 6th graders that are not in either band or orchestra.
  15 6th Graders in band
  9 6th Graders in both classes
+18 6th Graders in orchestra
-----
42 6th Graders in either class

  100 6th Graders in total
 -42 6th Graders in either class
-------
58 6th Graders in neither class
 58-42= 16 more 6th Graders that are not in either class
You're welcome :)

7 0
2 years ago
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