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Bumek [7]
3 years ago
7

The diagram shows a sector of a circle of radius 6 units, formed from an angle of size 310,

Mathematics
1 answer:
BARSIC [14]3 years ago
8 0

Answer:

32.47619

Step-by-step explanation:

length of the arc =310/360 ×2(22/7)×6

=32.47619 units

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Someone help me pleaseee​
Liono4ka [1.6K]

Answer:

A.) 588329.896

B.) 274300

C.) 1657.18474

D.) 1.002

(All answers unrounded.)

Explanation:

I converted each unit to the unit used in the other number (E.g., for question A I converted tons to kilograms, and then finished solving.)

7 0
2 years ago
4x + y =3<br> x + y - z = 9<br> 2x + 2y + z = 0
uranmaximum [27]

Answer:

[0, 3, -6]

Step-by-step explanation:

{4x + y = 3

{x + y - z = 9 ←

{2x + 2y + z = 0 ←

{4x + y = 3

{3x + 3y = 9 >> Combined equation

−¾[4x + y = 3]

{−3x - ¾y = −2¼ >> New Equation

{3x + 3y = 9

_________

2¼y = 6¾

___ ___

2¼ 2¼

y = 3 [Plug this back into all three equations to get the z-value of −6, and the x-value of 0]; 0 = x; -6 = z

I am joyous to assist you anytime.

4 0
3 years ago
A container weighs 23 2/5 pounds holds sports equipment. Of the equipment in the container 1/3 of the weight is baseball equipme
hram777 [196]
What we need to know is how much is 1/3 of 25 2/5.

We will be multiplying fraction by a fraction and for this, it's good to change mixed numbers into improper fractions:

25 2/5=\frac{23*5+2}{5}= \frac{117}{5}

and now we multiply it by 1/3:

\frac{1}{3}\frac{117}{5}=\frac{39}{5}=7\frac{4}{5}

and that's the answer: the basketball equipment weights 7 4/5 pounds.




8 0
2 years ago
If P(-4,-2) and Q(1, -3) represent points in a coordinate
Artyom0805 [142]

Answer:

the answer is (6, -4)

Step-by-step explanation:

4 0
3 years ago
The table gives the relative frequencies of recipes that contains sugar and salt, contain at least one of those ingredients, or
tigry1 [53]

<u>Answer-</u>

<em>The probability that a randomly selected recipe does not contain sugar, given that it contains salt is 22.4%</em>

<u>Solution-</u>

The given table in the link shows the relative frequencies of recipes that contains sugar and salt, or contains at least one of those ingredients, or contains neither of those ingredients.

We have to find the conditional probability that the recipe doesn't contain sugar, given that it contains salt.

We know that, the conditional probability of occurrence of A given that B occurs is,

P(A|B)=\frac{P(A\ and\ B)}{P(B)} =\frac{P(A\bigcap B)}{P(B)}

P(\text{Doesn't contain sugar}\ |\ \text{Contains salt})=\frac{P(\text{Doesn't contain sugar}\ and\ \text{Contains salt})}{P(\text{Contains salt})}


P(\text{Doesn't contain sugar}\ and\ \text{Contains salt})=\frac{0.15}{1} =0.15\\P(\text{Contains salt})=\frac{0.67}{1}=0.67

Putting these values,

P(\text{Doesn't contain sugar}\ |\ \text{Contains salt})=\frac{0.15}{0.67} =0.224=22.4\%

5 0
3 years ago
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