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Drupady [299]
3 years ago
11

Write 3/5 as a division

Mathematics
1 answer:
ollegr [7]3 years ago
3 0

Answer:

3/5 as a division is 0.6

Step-by-step explanation:

To write a fraction as a division, we basically divide the values, since the fraction represents a division.

In this question:

We want 3 divided by 5.

3 is less than 5, so we can multiply 3 by 10(getting 30), and adding a 0 to the quotient.

So now 0.(30/5) = 0.6, which means that 3/5 as a division is 0.6.

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A pentagon has the following side lengths 5 inches 3 inches 7 inches 4 inches and 3.5 in what is the perimeter of the Pentagon?
Svetllana [295]

Answer:

22.5 inches

Step-by-step explanation:

Perimeter is simply the measure of all sides of a shape. Simply add.

5+3+7+4+3.5=22.5

8 0
4 years ago
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If i was born in 2004 how old will i be in 2048
svet-max [94.6K]
2048-2004=44 years old. This assumes the same time of year.
5 0
3 years ago
6.7 more than the product of 5 and n
Harman [31]
The product of 5 and n is 5n. Since the expression is 6.7 more than this product, we add 6.7 to 5n. the expression becomes:

5n+6.7

6 0
3 years ago
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What are the orders of 3,7,9,11,13,17 and 19(mod20)?does 20 have primitive roots?
bezimeni [28]
3\equiv3\mod{20}
3^2\equiv9\mod{20}
3^3\equiv27\equiv7\mod{20}
3^4\equiv3\cdot3^3\equiv3\cdot7\equiv21\equiv1\mod{20}

7\equiv7\mod{20}
7^2\equiv49\equiv9\mod{20}
7^3\equiv7\cdot7^2\equiv63\equiv3\mod{20}
7^4\equiv7\cdot7^3\equiv21\equiv1\mod{20}

9\equiv9\mod{20}
9^2\equiv3^4\equiv1\mod{20}

11\equiv11\mod{20}
11^2\equiv121\equiv1\mod{20}

13\equiv-7\equiv13\mod{20}
13^2\equiv169\equiv9\mod{20}
13^3\equiv13\cdot13^2\equiv(-7)9\equiv-63\equiv-3\mod{20}
13^4\equiv13\cdot13^3\equiv(-7)(-3)\equiv21\equiv1\mod{20}

17\equiv-3\equiv17\mod{20}
17^2\equiv(-3)^2\equiv9\mod{20}
17^3\equiv(-3)^3\equiv-27\equiv3\mod{20}
17^4\equiv(-3)^4\equiv81\equiv1\mod{20}

19\equiv-1\equiv19\mod{20}
19^2\equiv19(-1)\equiv-19\equiv1\mod{20}

Generally speaking, a number x coprime to n will be a primitive root of n if we have x^n\equiv x\mod{n}, or x^{n-1}\equiv1\mod{n}. In other words, if x is of order n-1 modulo n, then x is a primitive root of n.

Since none of these numbers has order 19, it follows that 20 does not have any primitive roots.
6 0
4 years ago
Simplify the expression below.<br> 2x – 4y + 6 + 3x – 9y – 4
Dmitrij [34]

Answer:

5x - 13y + 2

Step-by-step explanation:

Given: 2x – 4y + 6 + 3x – 9y – 4

Combine all like terms:

5x - 13y + 2

8 0
3 years ago
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