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balandron [24]
3 years ago
8

Which graph shows the solution set for this inequality r + 9 < 12

Mathematics
2 answers:
kupik [55]3 years ago
6 0
Ima guess D because it would simplify to
r < 3

And I think without the line under the equality sign it’s an open circle so...

Arrow points left cause of the less than sign
melomori [17]3 years ago
3 0

Answer:

C

Step-by-step explanation:C

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A $280 suit is marked down by 20%. Find the sale price.
Liula [17]

Answer:

I believe its $56... 280*.20=56

Step-by-step explanation:

4 0
3 years ago
Solve the following inequality. 45 &lt; 9(x + 3) &lt; 153 A. 8 &lt; x &lt; 14 B. 2 &lt; x &lt; 20 C. 8 &lt; x &lt; 20 D. 2 &lt;
kaheart [24]

Answer:

B

Step-by-step explanation:

hope this help but I worked it out so it should be true

7 0
3 years ago
My room is 7½ ft by 8 ¼ ft. If I want to put a border around it l mid help​
victus00 [196]
9055&43882288273372737373
8 0
2 years ago
A sequence of Bernoulli trials consists of choosing components at random from a batch of components. A selected component is eit
Drupady [299]

Answer:

a) 0.0287 = 2.87% probability that three non-defective components in a batch of seven components.

b) 0.0336 = 3.36% probability that 8 non-defective components are drawn before the first defective component is chosen.

Step-by-step explanation:

A sequence of Bernoulli trials composes the binomial distribution.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

The probability that a selected component is non-defective is 0.8

This means that p = 0.8

a) Three non-defective components in a batch of seven components.

This is P(X = 3) when n = 7. So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 3) = C_{7,3}.(0.8)^{3}.(0.2)^{4} = 0.0287

0.0287 = 2.87% probability that three non-defective components in a batch of seven components.

b) 8 non-defective components are drawn before the first defective component is chosen.

Now the order is important, so the we just multiply the probabilities.

8 non-defective, each with probability 0.8, and then a defective, with probability 0.2. So

p = (0.8)^8*0.2 = 0.0336

0.0336 = 3.36% probability that 8 non-defective components are drawn before the first defective component is chosen.

4 0
3 years ago
Can u guys plz give me the answer to number 1-3
jek_recluse [69]
I'm pretty sure it is 5:55


8 0
3 years ago
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