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ololo11 [35]
2 years ago
9

X Y

Mathematics
1 answer:
aliina [53]2 years ago
4 0
The answer is B. I hope it help :)
You might be interested in
What is the equation of the midline for the function f(x)? f(x)=1/2 cos(x)+5
ivolga24 [154]

Answer:

y = 5

Step-by-step explanation:

That "+5" elevates the graph of this cosine function 5 units above the x axis, and thus the "midline" you wanted is  y = 5.

6 0
3 years ago
A merchant wants to establish the selling price of an item that costs him $4.50 with a 15% markup. What is his selling price?
OLga [1]

Answer:

the answer it $5.18

Step-by-step explanation:

$4.50 + ($4.50 x .15)

$4.50 + $0.68 = $5.18

4 0
3 years ago
Robert's dog is 4 years older than Karen's cat. In 3 years, the sum of the ages of Robert's dog and Karen's cat will be 13. How
mylen [45]

Answer:

5.5 years old.

Step-by-step explanation:

Let D represent present age of Robert's dog and C represent present age of Karen's cat.

We have been given that Robert's dog is 4 years older than Karen's cat. We can represent this information in an equation as:

D=C+4...(1)

We are also told that in 3 years, the sum of the ages of Robert's dog and Karen's cat will be 13. After 3 years age of dog and cat would be D+3 and C+3 respectively.

We can represent this information in an equation as:

D+3+C+3=13...(2)

From equation (1), we will get:

C=D-4

Upon substituting this value in equation (2), we will get:

D+3+D-4+3=13

Combine like terms:

2D+2=13

2D+2-2=13-2

2D=11

\frac{2D}{2}=\frac{11}{2}

D=5.5

Therefore, Robert's dog is 5.5 years old right now.

3 0
3 years ago
Colin pays £766.45 a year on his car insurance.
aliina [53]

Answer:

£807.84

Step-by-step explanation:

Cost of Collins car insurance per year = £766.45

Percentage increase in price = 5.4%

How much does the insurance cost now?

Cost of the insurance now = £766.45 + 5.4% of £766.45

= 766.45 + 5.4/100(766.45)

= 766.45 + 0.054(766.45)

= 766.45 + 41.3883

= 807.8383

Cost of the insurance now = £807.84

3 0
3 years ago
Find 4 consecutive odd numbers such that twice the sum of the least 2 numbers is 40 less than three times the sum of the greates
ANTONII [103]
4 consecutive odd numbers....x, x + 2, x + 4, x + 6

2(x + x + 2) = 3(x + 4 + x + 6) - 40
2(2x + 2) = 3(2x + 10) - 40
4x + 4 = 6x + 30 - 40
4x + 4 = 6x - 10
4x - 6x = -10 - 4
-2x = - 14
x = -14/-2
x = 7

x + 2 = 7 + 2 = 9
x + 4 = 7 + 4 = 11
x + 6 = 7 + 6 = 13

ur numbers are : 7,9,11,13 <==
4 0
3 years ago
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