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The life of a semiconductor laser at a constant power is normally distributed with a mean of 7,000 hours and a standard deviation of 600 hours. If three lasers are used in a product and they are assumed to fail independently, the probability that all three are still operating after 7,000 hours is closest to? Assuming percentile = 95%
Answer:
0.125
Step-by-step explanation:
Assuming for 95%
z score for 95th percentile = 1.645
We find the Probability using z table.
P(z = 1.645) = P( x ≤ 7000)
= P(x<Z) = 0.95
After 7000 hours = P > 7000
= 1 - P(x < 7000)
= 1 - 0.95
= 0.05
If three lasers are used in a product and they are assumed to fail independently, the probability that all three are still operating after 7,000 hours is calculated as:
(P > 7000)³
(0.05)³ = 0.125
Answer:
x = 25
Step-by-step explanation:
Given:
- ∠A = ∠B (Vertically opposite angles)
- ∠A = (7x - 8)°
- ∠B = (6x + 17)°
Since ∠A is equivalent to ∠B...
Open the parenthesis:
Add 8 both sides:
Simplify both sides:
Subtract 6x both sides:
Simplify both sides:
Step-by-step explanation:
Only 1 number works. 1 will make 819 which is divisible by 9.
Since it is 1 of ten numbers can go in the blank, the answer is 1/10 which is 0.1
The 10 number choices are
0,1,2,3,4,5,6,7,8,9
The only one that works is 1 as I've stated.
Answer:
Step-by-step explanation:
Given
The above table
Required
Determine the probability of a sum that is a multiple of 6
Represent the event that an outcome is a multiple of 6 with M.
List out all possible values of M
Number of M is
Total possible outcome is:
The theoretical probability is then calculated as follows:
In this case, it is:
Simplify fraction
