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OleMash [197]
3 years ago
7

How would you estimate the price if a shirt that usually costs $32.99 is on sale for 25% off?

Mathematics
2 answers:
Nuetrik [128]3 years ago
6 0

Answer:

32.99/4 is about 8.25

8.25 x 3= 24.75

about 24.75

Step-by-step explanation:

aksik [14]3 years ago
3 0
22.47 hdr. Ifrvh out
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Which of the following is an X-intercept of the function f(X)=X^3-5X^2-8X+48
Anton [14]
You have to searh the x values that make f(x) = 0

Factoring this equation is very difficult.

You can divide by x+3 and you will find that the equation can be factored as

(x+3)(x-4)^2

That means that x = -3 and x = 4 make f(x) = 0

Then the points are (-3,0) and (4,0).
6 0
3 years ago
Please can you help me anything will help please
Bumek [7]

Answer: 1, 2, 4, or 5

Step-by-step explanation:

The relationship in #3 is a function because all the x values are distinct, that is, none are repeated. (Y values don't matter.)

A function will not repeat any x values so if your goal is for the relationship in #4 to NOT be a function, repeat one of the x values. Any one will work.

4 0
3 years ago
CALCULUS - Find the values of in the interval (0,2pi) where the tangent line to the graph of y = sinxcosx is
Rufina [12.5K]

Answer:

\{\frac{\pi}{4}, \frac{3\pi}{4},\frac{5\pi}{4},\frac{7\pi}{4}\}

Step-by-step explanation:

We want to find the values between the interval (0, 2π) where the tangent line to the graph of y=sin(x)cos(x) is horizontal.

Since the tangent line is horizontal, this means that our derivative at those points are 0.

So, first, let's find the derivative of our function.

y=\sin(x)\cos(x)

Take the derivative of both sides with respect to x:

\frac{d}{dx}[y]=\frac{d}{dx}[\sin(x)\cos(x)]

We need to use the product rule:

(uv)'=u'v+uv'

So, differentiate:

y'=\frac{d}{dx}[\sin(x)]\cos(x)+\sin(x)\frac{d}{dx}[\cos(x)]

Evaluate:

y'=(\cos(x))(\cos(x))+\sin(x)(-\sin(x))

Simplify:

y'=\cos^2(x)-\sin^2(x)

Since our tangent line is horizontal, the slope is 0. So, substitute 0 for y':

0=\cos^2(x)-\sin^2(x)

Now, let's solve for x. First, we can use the difference of two squares to obtain:

0=(\cos(x)-\sin(x))(\cos(x)+\sin(x))

Zero Product Property:

0=\cos(x)-\sin(x)\text{ or } 0=\cos(x)+\sin(x)

Solve for each case.

Case 1:

0=\cos(x)-\sin(x)

Add sin(x) to both sides:

\cos(x)=\sin(x)

To solve this, we can use the unit circle.

Recall at what points cosine equals sine.

This only happens twice: at π/4 (45°) and at 5π/4 (225°).

At both of these points, both cosine and sine equals √2/2 and -√2/2.

And between the intervals 0 and 2π, these are the only two times that happens.

Case II:

We have:

0=\cos(x)+\sin(x)

Subtract sine from both sides:

\cos(x)=-\sin(x)

Again, we can use the unit circle. Recall when cosine is the opposite of sine.

Like the previous one, this also happens at the 45°. However, this times, it happens at 3π/4 and 7π/4.

At 3π/4, cosine is -√2/2, and sine is √2/2. If we divide by a negative, we will see that cos(x)=-sin(x).

At 7π/4, cosine is √2/2, and sine is -√2/2, thus making our equation true.

Therefore, our solution set is:

\{\frac{\pi}{4}, \frac{3\pi}{4},\frac{5\pi}{4},\frac{7\pi}{4}\}

And we're done!

Edit: Small Mistake :)

5 0
3 years ago
Рабочий изготовил за 1 час 17 деталей . А его ученик 12 деталей . Сколько деталей они изготовят за 7 часов совместной работы
Svetradugi [14.3K]

Answer:

203

Step-by-step explanation:

17*7=119

12*7=84

84+119=203

4 0
3 years ago
Simplify the following number by using the imaginary number i square root of -19
lakkis [162]

Answer:

Exact form:   -√19

Decimal form:  −4.35889894...

3 0
3 years ago
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