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BabaBlast [244]
3 years ago
10

Find the intersection of the line and the circle given below 2x+y=-5 x^2+y^2=10

Mathematics
2 answers:
e-lub [12.9K]3 years ago
7 0

Answer:

They intersect at (-3,1), and also (-1,-3)

Step-by-step explanation:

Graph:

dalvyx [7]3 years ago
3 0

Answer:

There are two intersections.

(-3,1) and (-1,-3)

Step-by-step explanation:

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A number added to five cubed.<br> Write an equation
Natali5045456 [20]

Answer:

x+5^3

Step-by-step explanation:

Let x be the number

cubed is raised to the third power

x+5^3

3 0
3 years ago
Factorise fully<br>-12a - 16 <br><br>please do quick, first to answer marked brainiest!!​
Allushta [10]

Answer:

-4( 3a+4)

Step-by-step explanation:

-12a - 16

-4*3a -4*4

Factor out a -4

-4( 3a+4)

3 0
3 years ago
Please solve this please​
ale4655 [162]

Answer:

C) \frac{2z+15}{6x-12y}

E) \frac{7d+5}{15d^2+14d+3}

F) \frac{-7a-b}{6b-4a}

Step-by-step explanation:

C)

One is given the following equation

\frac{z+1}{x-2y}-\frac{2z-3}{2x-4y}+\frac{z}{3x-6y}

In order to simplify fractions, one must convert the fractions to a common denominator. The common denominator is the least common multiple between the given denominators. Please note that the denominator is the number under the fraction bar of a fraction. In this case, the least common multiple of the denominators is (6x-12y). Multiply the numerator and denominator of each fraction by the respective value in order to convert the fraction's denominator to the least common multiple,

\frac{z+1}{x-2y}-\frac{2z-3}{2x-4y}+\frac{z}{3x-6y}

\frac{z+1}{x-2y}*\frac{6}{6}-\frac{2z-3}{2x-4y}*\frac{3}{3}+\frac{z}{3x-6y}*\frac{2}{2}

Simplify,

\frac{z+1}{x-2y}*\frac{6}{6}-\frac{2z-3}{2x-4y}*\frac{3}{3}+\frac{z}{3x-6y}*\frac{2}{2}

\frac{6z+6}{6x-12y}-\frac{6z-9}{6x-12y}+\frac{2z}{6x-12y}

\frac{(6z+6)-(6z-9)+(2z)}{6x-12y}

\frac{6z+6-6z+9+2z}{6x-12y}

\frac{2z+15}{6x-12y}

E)

In this case, one is given the problem that is as follows:

\frac{2}{3d+1}-\frac{1}{5d+3}

Use a similar strategy to solve this problem as used in part (c). Please note that in this case, the least common multiple of the two denominators is the product of the two denominators. In other words, the following value: ((3d+1)(5d+3))

\frac{2}{3d+1}-\frac{1}{5d+3}

\frac{2}{3d+1}*\frac{5d+3}{5d+3}-\frac{1}{5d+3}*\frac{3d+1}{3d+1}

Simplify,

\frac{2}{3d+1}*\frac{5d+3}{5d+3}-\frac{1}{5d+3}*\frac{3d+1}{3d+1}

\frac{2(5d+3)}{(3d+1)(5d+3)}-\frac{1(3d+1)}{(5d+3)(3d+1)}

\frac{10d+6}{(3d+1)(5d+3)}-\frac{3d+1}{(5d+3)(3d+1)}

\frac{(10d+6)-(3d+1)}{(3d+1)(5d+3)}

\frac{10d+6-3d-1}{(3d+1)(5d+3)}

\frac{7d+5}{(3d+1)(5d+3)}

\frac{7d+5}{15d^2+14d+3}

F)

The final problem one is given is the following:

\frac{3a}{2a-3b}-\frac{a+b}{6b-4a}

For this problem, one can use the same strategy to solve it as used in parts (c) and (e). The least common multiple of the two denominators is (6b-4a). Multiply the first fraction by a certain value to attain this denomaintor,

\frac{3a}{2a-3b}-\frac{a+b}{6b-4a}

\frac{3a}{2a-3b}*\frac{-2}{-2}-\frac{a+b}{6b-4a}

Simplify,

\frac{3a}{2a-3b}*\frac{-2}{-2}-\frac{a+b}{6b-4a}

\frac{-6a}{6b-4a}-\frac{a+b}{6b-4a}

\frac{(-6a)-(a+b)}{6b-4a}

\frac{-6a-a-b}{6b-4a}

\frac{-7a-b}{6b-4a}

4 0
3 years ago
Solve: a + 4 = 48<br> a = 43<br> a = 51<br> a = 44<br> a = 52
andrew11 [14]

Answer:

a = 44 is correct

Step-by-step explanation:

a + 4 = 48

plug in the #'s 1 at a time

43 + 4 = 48

47 = 48  FALSE

51 + 4 = 48

55 = 48  FALSE

44 + 4 = 48  TRUE

52 + 4 = 48  FALSE

Hope this Helps!!!

5 0
3 years ago
What is the area of this figure? Use 3.14 for pi.
andrey2020 [161]

Answer:

24,53cm²

Step-by-step explanation:

rectangle area=length×width=7×3

=21cm²

circle area=1/2Π r²

=1/2×3.14×1.5×1.5

=3.5325cm²

add the two areas

21+3.53=24,53cm²

6 0
3 years ago
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