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2 years ago

5, 10, 12, 4, 6, 11, 13, 5 calculate the median show your work

Mathematics

2 answers:

Zinaida [17]2 years ago

8 0

First you want to organize it from least to greatest: 4, 5, 5, 6, 10, 11, 12, 13

Then look for the one in the middle. But oh wait there are 2 so you need to add 6 and 10 then divide it by 2 to get a median of 8.

A song I learned back then is this I don't know who it is by though: Mode, mode, mode is the most, Average is the mean.Median, median, median, median, The number in between.

nexus9112 [7]2 years ago

5 0

First you put the numbers n order the n figurw it out on our own

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Help me with this please

Aleks04 [339]

Answer:

187.5 m^3

Step-by-step explanation:

2 to 5 is 2(2.5)

2.5^2 = 6.25

6.25(30) = 187.5

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1 year ago

A triangular prism has base edges 4cm, 5cm, and 6cm long. Its lateral area is 300 cm2. What's the height if the prism?

almond37 [142]

Answer: For your specific problem, h = 300 / (4 + 5 + 6) = 300 / 15 = 20

Step-by-step explanation:

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2 years ago

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taurus [48]

Answer:

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Step-by-step explanation:

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1 year ago

Circle the table the represents a linear relationship.

nata0808 [166]

2nd one because it’s not a lot of big number I hope it helps

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2 years ago

The length of each side of an equilateral triangle is increased by 20%, resulting in triangle ABC. If the length of each side of

kompoz [17]

Answer: Area of ΔABC is 2.25x the area of ΔDEF.

Step-by-step explanation: Because equilateral triangle has 3 equal sides, area is calculated as

$A=\frac{\sqrt{3} }{4} a^{2}$

with a as side of the triangle.

Triangle ABC is 20% bigger than the original, which means its side (a₁) measures, compared to the original:

a₁ = 1.2a

Then, its area is

$A_{1}=\frac{\sqrt{3} }{4}(1.2a)^{2}$

$A_{1}=\frac{\sqrt{3} }{4}1.44a^{2}$

Triangle DEF is 20% smaller than the original, which means its side is:

a₂ = 0.8a

So, area is

$A_{2}=\frac{\sqrt{3} }{4} (0.8a)^{2}$

$A_{2}=\frac{\sqrt{3} }{4} 0.64a^{2}$

Now, comparing areas:

$\frac{A_{1}}{A_{2}}= (\frac{\sqrt{3}.1.44a^{2} }{4})(\frac{4}{\sqrt{3}.0.64a^{2} } )$

$\frac{A_{1}}{A_{2}} =$ 2.25

The area of ΔABC is 2.25x greater than the area of ΔDEF.

7 0

2 years ago