Question

What is the area of a rectangle with vertices (2, 3), (9, 3), (9, Negative 2), and (2, Negative 2)? square units

Answer 1

Answer:

Area of the rectangle = $35\,\,units^2$

Step-by-step explanation:

Area of the Rectangle= Product of the two Unequal sides

Finding the two unequal sides of the rectangle using the distance formula:

For the coordinates:

A(2,3)  B(9,3)  C(9,-2)  D(2,-2)

Using Distance formula:

AB=

            $=\sqrt{(9-2)^2+(3-3)^2} \\\\=\sqrt{7^2+0} \\\\=\sqrt{49}\\\\ =7\,\,units$

Similarly, BC= 5 units

Area of the rectangle is:

                                 $=7\times 5\\\\=35\,\,units^2$