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3 years ago

I want the answer please!

Mathematics

2 answers:

agasfer [191]3 years ago

8 0

Answer:

x = 38 degrees.

The angle marked 2x-1 =75 degrees

Step-by-step explanation:

the opposite angles of a parallelogram are equal.

so:

2x -1 = 75

2x = 76

x = 38

Hope this helps

ElenaW [278]3 years ago

4 0

Answer:

x=38

Step-by-step explanation:

A quadrilateral's interior angles add up to 360°

In a parallelogram, the sides diagonal from it are the same angle measure. This mean that ∠K is 105° and ∠L is 75°. From this, we get:

2x-1=75

Add 1 to both sides

2x=76

Divide both sides by 2

x=38

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katrin2010 [14]

It would take around 2.08 hours - first you find the MPH which would be 268, and then you divide 560 and 268.

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4 years ago

Select all possible solutions for 2x+7 ≤ 3x-5

Leto [7]

2x+7 <= 3x-5

subtract 2x from each side

7 <= x-5

add 5 to each side

12 <= x

x must be greater than or equal to 12

12 18 24 and 107 are possible solutions

4 0

4 years ago

I NEED HELP PLS THIS IS DUE IN 3 HOURS

Mariulka [41]

Answer:

Part 1) $x^{2} -2x-2=(x-1-\sqrt{3})(x-1+\sqrt{3})$

Part 2) $x^{2} -6x+4=(x-3-\sqrt{5})(x-3+\sqrt{5})$

Step-by-step explanation:

we know that

The formula to solve a quadratic equation of the form

$ax^{2} +bx+c=0$

is equal to

$x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}$

Part 1)

in this problem we have

$x^{2} -2x-2=0$

$a=1\\b=-2\\c=-2$

substitute in the formula

$x=\frac{-(-2)(+/-)\sqrt{-2^{2}-4(1)(-2)}} {2(1)}\\\\x=\frac{2(+/-)\sqrt{12}} {2}\\\\x=\frac{2(+/-)2\sqrt{3}} {2}\\\\x_1=\frac{2(+)2\sqrt{3}} {2}=1+\sqrt{3}\\\\x_2=\frac{2(-)2\sqrt{3}} {2}=1-\sqrt{3}$

therefore

$x^{2} -2x-2=(x-(1+\sqrt{3}))(x-(1-\sqrt{3}))$

$x^{2} -2x-2=(x-1-\sqrt{3})(x-1+\sqrt{3})$

Part 2)

in this problem we have

$x^{2} -6x+4=0$

$a=1\\b=-6\\c=4$

substitute in the formula

$x=\frac{-(-6)(+/-)\sqrt{-6^{2}-4(1)(4)}} {2(1)}$

$x=\frac{6(+/-)\sqrt{20}} {2}$

$x=\frac{6(+/-)2\sqrt{5}} {2}$

$x_1=\frac{6(+)2\sqrt{5}}{2}=3+\sqrt{5}$

$x_2=\frac{6(-)2\sqrt{5}}{2}=3-\sqrt{5}$

therefore

$x^{2} -6x+4=(x-(3+\sqrt{5}))(x-(3-\sqrt{5}))$

$x^{2} -6x+4=(x-3-\sqrt{5})(x-3+\sqrt{5})$

5 0

4 years ago

Calcular cuántos números impares hay entre 20 y 50 y calcular su suma

const2013 [10]

Answer:

La suma de los impares entre 20 y 50 da 875

Step-by-step explanation:

Suma de Progresiones Artiméticas

Una progresión aritmética es aquella en la cual, cada término se obtiene como el anterior mas una cantidad fija llamada diferencia común. El término general de una progresión aritmética es

$a_n=a_1+(n-1)r$

Donde $a_1$ es el primer término, n el número de términos y r la diferencia común o radio. La suma de los primeros n términos se calcula como:

$\displaystyle S_n=n\frac{a_1+a_n}{2}$

En nuestro ejercicio, se deben sumar los números impares entre 20 y 50, se forma la progresión

21, 23, 25, 27, ....49

Sabemos que $a_1=21,\ a_n=49,\ r=2$

Primero averiguamos cuántos términos son, despejando n del término general

$\displaystyle n=\frac{a_n-a_1}{r}+1$

$\displaystyle n=\frac{49-21}{2}+1$

$\displaystyle n=25$

La progresión tiene 25 términos

Ahora la suma es

$\displaystyle S_{25}=25\frac{21+49}{2}$

$\displaystyle S_{25}=25\frac{70}{2}$

$S_{25}=875$

La suma de los impares entre 20 y 50 da 875

6 0

4 years ago

Suppose the population of a certain city is 4735 thousand it is expected to decrease to 4049 thousand in 50 years. find the perc

Yuki888 [10]

Working out

$\frac{(4735 - 4049)}{4735} \times 100$
Percentage= Difference/Original value x 100

Difference =4735-4049=686

P=686/4735

=0.1448... × 100

=14.5

4 0

3 years ago