This graph is the parent function of quadratic functions True or false

nexus9112 [7]

Answer:

the one on the right looks best for the slope because the slope is a lot larger than the one on the right the one on the right is smaller but a few inches few times I don't know you might want to check it before I actually answer it for you so I hope you found this kind of helpful thank you bye

5 0

3 years ago

What is the probability that a randomly dropped marker will fall in the unshaded region?

statuscvo [17]

The correct answer is 14 by 15

7 0

4 years ago

Read 2 more answers

Elizabeth lives in San Francisco and works in Mountain View. In the morning, she has 3 transportation options (take a bus, a cab

Lesechka [4]

Answer:

4/9

Step-by-step explanation:

The possibilities of transportation: (The first will be for morning, second will be for afternoon)

B, B

B, C

B, T

C, B

C, C

C, T

T, B

T, C

T, T

It is clearly seen that there are 9 transportation options.

(Using cab 1 time we have BC, CB, CT, TC. So four of the transportation methods use cab one time.)

Therefore, the probability that she will use a cab only once is 4/9.

6 0

3 years ago

Please help me with this homework question. No silly answers please and no bots! I will mark brainliest to whoever gets all them

MatroZZZ [7]

Answer:

The formula for the area of the triangle is:

$\displaystyle A=24x^2$

When x = 3, the area is 216 square centimeters.

When x = 2.4, the area is 138.24 square centimeters.

And when x = 5, the hypotenuse of the triangle is 50 centimeters.

Step-by-step explanation:

We are given a right triangle with a height of 8x and a base of 6x.

The area of a triangle is given by the formula:

$\displaystyle A=\frac{1}{2}bh$

So, by substitution:

$\displaystyle A=\frac{1}{2}(8x)(6x)=24x^2$

When x = 3, the area will be:

$\displaystyle A(3)=24(3)^2=216\text{ cm}^2$

And when x = 2.4, the area will be:

$A(2.4)=24(2.4)^2=138.24\text{ cm}^2$

When x = 5, the height will be 8(5) = 40 cm and the base will be 6(5) = 30 cm.

By the Pythagorean Theorem:

$a^2+b^2=c^2$

So:

$(40)^2+(30)^2=c^2$

The hypotenuse will be:

$c=\sqrt{1600+900}=\sqrt{2500}=50\text{ cm}$

3 0

3 years ago

Hey could someone please help me with this really hard assignment is taking me forever. Thank you marking brainliest!

rewona [7]

Answer:

Exercise 1: The length of the unknown leg is 4 inches.

Exercise 3: The following straws can be used to construct the triangle: b) $3\,in$ , c) $4.5\,in$ , d) $6.5\,in$ , e) $10\,in$ , f) $13.5\,in$

Exercise 4: Possible options of this exercise: 1) (2, 4, 5), 2) (4, 5, 6), 3) (5, 6, 10), 4) (1, 2, 11), 5) (1, 4, 11), 6) (1, 10, 11)

Step-by-step explanation:

Exercise 1:

Let suppose that triangle represented in the figure is a right triangle, the length of the missing leg is determined by Pythagorean Theorem:

$y = \sqrt{l^{2}-x^{2}}$ (1)

Where:

$l$ - Hypotenuse, in inches.

$x$ - Known leg, in inches.

$y$ - Unknown leg, in inches.

If we know that $l = 11\,in$ and $x = 10\,in$ , then the length of the unknown leg is:

$y = \sqrt{21}$

Since 4 is the least whole number closest to $\sqrt{21}$ , then we conclude that the length of the unknown leg is 4 inches.

Exercise 3:

The range of possible lengths for the missing side of the triangle is represented by the following simultaneous inequality:

$x + y > l > x-y$ (2)

Where:

$x$ - Greater side, in inches.

$y$ - Lesser side, in inches.

$l$ - Missing side, in inches.

If we know that $x = 8\,in$ and $y = 6\,in$ , then we have the following range of missing sides:

$14\,in > l > 2\,in$

The following straws can be used to construct the triangle: b) $3\,in$ , c) $4.5\,in$ , d) $6.5\,in$ , e) $10\,in$ , f) $13.5\,in$

Exercise 4:

Let check each pair to determine possible constructions by means of the inequality used in Exercise 3:

(i) $x = 4\,in, y = 2\,in$

$6\,in>l>2\,in$

Possible choices: 5 inches.

(ii) $x = 5\,in, y = 2\,in$

$7\,in > l > 3\,in$

Possible choices: 4 inches, 6 inches.

(iii) $x = 6\,in, y = 2\,in$

$8\,in > l > 4\,in$

Possible choices: 5 inches, 6 inches.

(iv) $x = 10\,in, y = 2\,in$

$12\,in > l > 8\,in$

Possible choices: None.

(v) $x = 5\,in, y = 4\,in$

$9\,in > l > 1\,in$

Possible choices: 2 inches, 6 inches.

(vi) $x = 6\,in, y = 4\,in$

$10\,in > l > 2\,in$

Possible choices: 5 inches.

(vii) $x = 10\,in, y = 4\,in$

$14\,in > l > 6\,in$

Possible choices: None.

(viii) $x = 6\,in, y = 5\,in$

$11\,in > l > 1\,in$

Possible choices: 2 inches, 4 inches, 10 inches.

(ix) $x = 10\,in, y = 5\,in$

$15\,in > l > 5\,in$

Possible choices: 6 inches.

(x) $x = 10\,in, y = 6\,in$

$16\,in > l > 4\,in$

Possible choices: 5 inches.

Possible options of this exercise: 1) (2, 4, 5), 2) (4, 5, 6), 3) (5, 6, 10), 4) (1, 2, 11), 5) (1, 4, 11), 6) (1, 10, 11)

7 0

3 years ago

Read 2 more answers