It could be parallelogram but square is always true
Answer:
(5, 0 )
Step-by-step explanation:
Given the 2 equations
y = x² - 2x - 15 → (1)
y = 8x - 40 → (2)
Substitute y = x² - 2x - 15 into (2)
x² - 2x - 15 = 8x - 40 ( subtract 8x - 40 from both sides )
x² - 10x + 25 = 0 ← in standard form
(x - 5)² = 0 ← in factored form, thus
x - 5 = 0 ⇒ x = 5
Substitute x = 5 into (2) for corresponding value of y
y = 8(5) - 40 = 40 - 40 = 0
Solution is (5, 0 )
Answer:
-4b^3 + b^2
Step-by-step explanation:
Answer:
−4304
Step-by-step explanation:
1. The given determinant is :
We need to find its determinant . It can be solved as follows :
So, the value of determinant is equal to −4304.
I believe the correct answer from the choices listed above is option A. If DF+FE=DE, then point F is <span>A. a midpoint of DE (with line over). F is the endpoint of line segment DF and is the starting point of line DE thus it is in between line DE. Hope this answers the question.</span>
