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JulsSmile [24]
3 years ago
10

What is the answer to 56.40-3.67

Mathematics
1 answer:
Oksi-84 [34.3K]3 years ago
5 0

Answer: 52.73

Explain: 56.40 - 3.67 = 52.73

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Friends needs this anwsered help
olya-2409 [2.1K]

Answer:

  3, 8, 14, 30, 58

Step-by-step explanation:

As with all formulas, put the numbers in place of the corresponding variables, and do the arithmetic.

  a_1=3\qquad\text{given}\\\\a_2=8\qquad\text{given}\\\\a_3=2a_1+a_2=2(3)+8=14\\\\a_4=2a_2+a_3=2(8)+14=30\\\\a_5=2a_3+a_4=2(14)+30=58

The first 5 terms of the sequence are 3, 8, 14, 30, 58.

4 0
2 years ago
8 The graph of y = a cos(x + b) for 0 2<br> 1<br> 60<br> 120<br> 180<br> 240<br> 300<br> 360<br> -1<br> -2<br> (a) Find the valu
MAVERICK [17]

Answer:

hw que no te he podido contestar por la tarde pero si te llamo en el tercero para que

8 0
2 years ago
in 2000 you weighed 175 pounds. in 2001 you weighed 62 pounds, and in 2002 you weighed 154 pounds. how many pounds did you lose
never [62]
You should get the answer 154 afte u subtract and at that school be your answer
6 0
3 years ago
HELP ASAP! LOOK AT PIC PLS
ra1l [238]

Answer:

E

Step-by-step explanation:

well, yes we know what coins there are and that they’re in jars right? but to find which jar is worth the most, we need to know how many coins are in each. she could have 300 pennies, 2 quarters, 4 dimes, and 7 nickels. we need more information to answer this question so E is the only correct option!

6 0
3 years ago
How many ways are there to select a 5-card hand from a regular deck such that the hand contains at least one card from each suit
Snezhnost [94]

Answer:

There are 685464 ways of selecting the 5-card hand

Step-by-step explanation:

Since the hand has 5 cards and there should be at least 1 card for each suit, then there should be 3 suits that appear once in the hand, and one suit that apperas twice.

In order to create a possible hand, first we select the suit that will appear twice. There are 4 possibilities for this. For that suit, we select the 2 cards that appear with the respective suit. Since there are 13 cards for each suit, then we have {13 \choose 2} = 78 possibilities. Then we pick one card of all remaining 3 suits. We have 13 ways to pick a card in each case.

This gives us a total of 4*78*13³ = 685464 possibilities to select the hand.

6 0
3 years ago
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