The fractions less than 1/2 are:
A. 1/3
C. 2/5
Answer:
11x+4+5=180 ok first we have to put all the naked numbers on one side and the x's number on one side, and by doing that a easier way to do that is you switch the spots but their symbols - and + change so if its negative - its going to turn into a + positive and + to a -
11x = 180 - 5 - 4
11x = 171 and since theres mutliplication 11 times x which is 11x, were going to divide
x = 171/11 and the out come is with decimals (15.54545...etc)
x=11 is incorrect
~batmans wife dun dun dun....
Answer:
Class interval 10-19 20-29 30-39 40-49 50-59
cumulative frequency 10 24 41 48 50
cumulative relative frequency 0.2 0.48 0.82 0.96 1
Step-by-step explanation:
1.
We are given the frequency of each class interval and we have to find the respective cumulative frequency and cumulative relative frequency.
Cumulative frequency
10
10+14=24
14+17=41
41+7=48
48+2=50
sum of frequencies is 50 so the relative frequency is f/50.
Relative frequency
10/50=0.2
14/50=0.28
17/50=0.34
7/50=0.14
2/50=0.04
Cumulative relative frequency
0.2
0.2+0.28=0.48
0.48+0.34=0.82
0.82+0.14=0.96
0.96+0.04=1
The cumulative relative frequency is calculated using relative frequency.
Relative frequency is calculated by dividing the respective frequency to the sum of frequency.
The cumulative frequency is calculated by adding the frequency of respective class to the sum of frequencies of previous classes.
The cumulative relative frequency is calculated by adding the relative frequency of respective class to the sum of relative frequencies of previous classes.
Answer:
y = 2x - 8
Step-by-step explanation:
Parallel lines have SIMILAR <em>RATE OF</em><em> </em><em>CHANGES</em><em> </em>[<em>SLOPES</em>], so 2 remains the same:
8 = 2[8] + b
↑
16
-8 = b
y = 2x - 8 >> Parallel Equation
I am joyous to assist you anytime.
